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Rina8888 [55]
3 years ago
11

#2 , #4 , #6 , #8 , #10 please

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0
2)
(4.18  x 10^-4)(9 x 10^-4)
= (4.18 x 9)(10^-4 x 10^-4)
= 37.62 x 10^-8
= 3.762 x 10^-7

4)
(9.45 x 10^10) / (1.5 x 10^6)
=(9.45 / 1.5) (10^10 / 10^6)
= 6.3 x 10^4

6)
(9 x 10^-11) / (2.4 x 10^8)
= (9 / 2.4) (10^-11 / 10^8)
= 3.75 x 10^-19

8)
(9.5 x 10^11) + (6.3 x 10^9)
= 10^9 (950 + 6.3)
= 956.3 x 10^9
= 9.563 x 10^11

10)
(1.357 x 10^9) + 590,000
= (1.357 x 10^9) + (5.9 x 10^5)
= 10^5 (13,570 + 5.9)
=13,575.9 x 10^5
= 1.35759 x 10^9
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brainliest?? Which transformation or sequence of transformations would produce an image that is not congruent to its pre‐image?
antoniya [11.8K]

Answer:

Brainliest!!!

Step-by-step explanation:

options:

A. A translation of 3 units to the left followed by a reflection across the x-axis

B. A rotation of 90 clockwise followed by a translation of 6 units to the left

C. A translation of 5 units to the left followed by a dilation of a factor of 2

D. A reflection across the y-axis followed by a rotation of 180 counterclockwise

All the other options deal with transformatios that just move the figure without modifying their dimmenssions.

When you dilate a figure you increase the dimmenssions, so the result is a different figure.

the answer is C

5 0
3 years ago
Read 2 more answers
T/18 = 7/100 solve for t
Vlad [161]

Answer:

t = 63/50 , t = 1.26, t = 1 13/50

Step-by-step explanation:

math

7 0
4 years ago
Read 2 more answers
Anthony wants to find the value of k for which given points W(0,-2), I(2,0) and L(5,k) are collinear
Bogdan [553]

Given:

The three points are W(0,-2), I(2,0) and L(5,k).

To find:

The value of k for which the given points are collinear.

Solution:

We know that, three points are collinear if the area of the triangle formed by these three points is 0.

\dfrac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|=0

x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)=0

The three points are W(0,-2), I(2,0) and L(5,k). So,

0(0-k)+2(k-(-2))+5(-2-0)=0

0+2(k+2)+5(-2)=0

2k+4-10=0

2k-6=0

Adding 6 on both sides, we get

2k=6

k=\dfrac{6}{2}

k=3

Therefore, the correct option is E.

5 0
3 years ago
Please match each function formula with the corresponding transformation of the parent function y= -x^2-1
pishuonlain [190]

Answer:

The answer in the attached figure

Step-by-step explanation:

we have the parent function

y=-x^{2}-1

case 1) <u>Reflected across the x-axis</u>

we know that

The rule of the transformation is

(x,y)------> (x,-y)

so

y=-(-x^{2}-1)

y=x^{2}+1

case 2) <u>Reflected across the y-axis</u>

we know that

The rule of the transformation is

(x,y)------> (-x,y)

so

y=-(-x)^{2}-1

y=-x^{2}-1

case 3) Translated left by 1 unit

we know that

The rule of the transformation is

(x,y)------> (x-1,y)

so

y=-(x+1)^{2}-1

case 4) Translated right by 1 unit

we know that

The rule of the transformation is

(x,y)------> (x+1,y)

so

y=-(x-1)^{2}-1

case 5) Translated down by 1 unit

we know that

The rule of the transformation is

(x,y)------> (x,y-1)

so

y=-(x)^{2}-1-1

y=-(x)^{2}-2

case 6) Translated up by 1 unit

we know that

The rule of the transformation is

(x,y)------> (x,y+1)

so

y=-(x)^{2}-1+1

y=-(x)^{2}

8 0
3 years ago
What’s the answer? All answers please
Doss [256]

Answer:

11. no solution

12. 12, -12.

13. 4/3, -4/3.

14. 6/5, -6/5.

15. 1/2, -1/2.

16. 7/4, -7/4.

Step-by-step explanation:

11. Why it is no solution is when you minus 66 from 3 you get a -63. You then divide 7 by that to get -9. Every time you put a negative inside a square root it will equal no solution every time.

12. 1/2x^2+3=75. I minused the 3 from both sides.

1/2x^2=72. I then times 1/2 to both sides to get 144.

x^2=144. I then square rooted both sides to get 12, -12.

13. 9x^2-16=0. I added 16 to both sides.

9x^2=16. I then divided 9 to both sides.

x^2=16/9. I then square rooted both sides to get 4/3, -4/3.

14. 25x^2+10=46. I minused the 10 from both sides.

25^2=36. I then divided 25 from both sides.

x^2=36/25. I then square rooted both sides to get 6/5, -6/5.

15. 5x^2-1=x^2. I minused x^2 from both sides.

4x^2-1=0. I added 1 to both sides.

4x^2=1. I divided 4 to both sides.

x^2=1/4. I square rooted both sides to get 1/2, -1/2.

16. 16x^2-34=15. I added 34 to both sides.

16x^2=49. I divided 16 to both sides.

x^2=49/16. I square rooted both sides to get 7/4, -7/4.

If you plug those answers into the equations. It should equal what it is equal to.  

3 0
3 years ago
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