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Oxana [17]
3 years ago
14

Callie loves flowers. She picks 4 tulips for every Daisy she picks. Callie's mom also gave her 6 tulips this week from her garde

n. How many flowers will Callie have this week if she picks 3 daisies? Explain
Mathematics
1 answer:
Setler [38]3 years ago
3 0

Answer:

18

Step-by-step explanation:

6 times 3 equals 18

4 times 3 equals 12 plus 6 equals 18

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OLZ HELP ILL MARK AS BRAINLEST
zhuklara [117]

Answer:

Step-by-step explanation:

Sam published his first book, a collection of poetry, at the age of 16.

3 0
2 years ago
PLEASE HELP ME this is really hard please
krok68 [10]

Answer:

  1100

  2200

Step-by-step explanation:

Since speed is constant, the distance is proportional to the time. We notice that the number in the second column is 1650/3 = 550 times the number in the first column, so the two missing numbers are ...

  2 × 550 = 1100

  4 × 550 = 2200

7 0
3 years ago
f(x) = square root ( x^4 -16x^2) let f be the function given by: . . a) Find the domain of f.. b) Find f '(x). c) Find the slope
Bond [772]
A ) The domain:
x^{4} -16 x^{2}  \geq 0 \\  x^{2} ( x^{2} -16) \geq 0 \\  x^{2} -16 \geq 0 \\  x^{2}  \geq 16
x ≤ -4  and x≥ 4  or:  x ∈ ( - ∞ , - 4 ) ∪ ( 4  , + ∞ )
b ) f ` ( x ) = \frac{1}{2 \sqrt{ x^{4} -16 x^{2} } } *( 4 x^{3} - 32 x ) = \\ = \frac{2x( x^{2} -8)}{ \sqrt{ x^{4}-16 x^{2}  } }
c ) The slope of the line normal to the graph at x = 5
m = -1 / f `(x)
f ` ( x ) = \frac{10(25-8)}{ \sqrt{625-400} }=  \frac{10*17}{15} = \frac{34}{3}
m = - 3/34 

8 0
3 years ago
A TV has an original price of $499. What is the new price after a 15% increase?
liubo4ka [24]

Given:

Original price of a TV = $499

Price increased by 15%.

To find:

The new price of the TV.

Solution:

According to the question,

New price of the TV = Original price + 15% of its original price.

\text{New price of the TV}=499+\dfrac{15}{100}(499)

\text{New price of the TV}=499+74.85

\text{New price of the TV}=573.85

Therefore, the new price of the TV is $573.85.

3 0
3 years ago
Identify the center and the radius of a circle that has a diameter with endpoints at (−5, 9) and (3, 5)
marusya05 [52]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}

8 0
3 years ago
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