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2 years ago

11

16 is 25% of what number

2 answers:

puteri [66]2 years ago

4 0

To set this as an equation, you could use 16 = x/4. X = 64

vesna_86 [32]2 years ago

3 0

'is' in mathematics means equal
'of' in mathematics means multiplication

If we translate "16 is 25% of what number" into a mathematical equation, we get:

16 = 25% * x

25% can also be expressed as 25/100, since % or percent means over 100.

16 = 25/100 * x
16 = 0.25 * x

x = 16/0.25

x = 64

16 is 25% of 64<span>.</span>

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Haruka hiked several kilometers in the morning. She hiked only 6 kilometers in the afternoon, which was 25%, percent less than s

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Answer:

14 km

Step-by-step explanation:

6 km in the afternoon

x km in the morning

6= x- 25%

6= 0.75x

x= 6/0.75

x= 8 km

total 6+8= 14 km

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3 years ago

How many fluid ounces in 8 ounces and 5 cups?

xenn [34]

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3 years ago

A ferris Wheel has a radius of 65 feet. What is the circumference of the wheel?

MAXImum [283]

Answer:

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7 0

2 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago

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MatroZZZ [7]

Answer:

hlo XD

no its not looking difficult

it is difficult

6 0

2 years ago