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4 years ago

A. 12 sin 40°

Mathematics

1 answer:

77julia77 [94]4 years ago

4 0

Answer:

what shall we do with a drunken sailor

Step-by-step explanation:

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What is the probability of landing on heads when flipping a fair coin?

olga2289 [7]

Answer:

1/2

Step-by-step explanation:

there are two results since there is heads and tails

7 0

4 years ago

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Jeff collects toy cars. they are displayed in a case that has 4 rows. there are 6 cars in each row. how many cars does jeff have

lilavasa [31]

24.

6 Cars * 4 Rows = 24 Cars

8 0

3 years ago

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The perimeter of a rectangle is 54cm. The area of the same rectangle is 176 cm^2. What are the dimensions of the rectangle?

densk [106]

Given is rectangle with perimeter = 54 centimeters and area = 176 squared centimeters.

Let's consider the length of rectangle = L and width of rectangle = W.

We know the following formulas for rectangle :-

Perimeter = 2 x (L + W)

Area = L x W

So we have 2 x (L + W) = 54 and L x W = 176.

L + W = 27 and L x W = 176

We need to find two positive integers such that their sum is 27 and product is 176.

Using trial and error, we have two such positive integers such that 11 + 16 = 27 and 11 x 16 = 176.

So, the dimensions of rectangle would be 11cm x 16cm.

Hence, option A is correct i.e. 11 cm by 16 cm.

3 0

3 years ago

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

3 years ago

The file size of an electronic book is 3.6 megabytes. What is the file size of 18 of these electronic books?

vichka [17]

Answer:

64.8

Step-by-step explanation:

3.6 megabytes ×18 books = 64.8 megabytes

4 0

3 years ago