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3 years ago

Question: (look at image above) (giving 25 points, please DONT COMMENT IF U DONT KNOW)

Mathematics

1 answer:

Katen [24]3 years ago

8 0

Answer:

The only two that share both of these qualities are the isosceles triangle and the isosceles right triangle.

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Simplify the following. (9x2+7x-6)+(9x2-7x+6)

kipiarov [429]

Answer:

9 x 2 + 7x

18 + 7x - 6

18 - 6 = 12

12 + 7x

Is your simplified expression

6 0

3 years ago

How exactly do you do this I understand this a little more but need a little push :(

Hitman42 [59]

Answer:

(2, 12)

Step-by-step explanation:

You do it by adding

2 and 0.

4 and 8.

3 0

3 years ago

Jo is 5cm taller than Kathy.Let j=jo height.Then? =kathys height.

xxMikexx [17]

Answer:

Kathy = J - 5 cm

Step-by-step explanation:

Jo = 5 + Kathy

Jo = J

Kathy = K

=> J = 5 + K

=> J - 5 = 5 - 5 + K

=> J - 5 = K

=> K = J - 5

So, Kathy's height is J - 5 cm

8 0

3 years ago

A = √7 + √c and b = √63 + √d where c and d are positive integers.

mrs_skeptik [129]

Answer:

$\displaystyle a:b=\frac{1}{3}$

Step-by-step explanation:

Ratios

We are given the following relations:

$a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]$

$b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]$

$\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]$

From [3]:

$9c=d$

Replacing into [2]:

$b=\sqrt{63}+\sqrt{9c}$

We can express 63=9*7:

$b=\sqrt{9*7}+\sqrt{9c}$

Taking the square root of 9:

$b=3\sqrt{7}+3\sqrt{c}$

Factoring:

$b=3(\sqrt{7}+\sqrt{c})$

Find the ration a:b:

$\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}$

Simplifying:

$\boxed{a:b=\frac{1}{3}}$

3 0

3 years ago

A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60

Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at t time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0

3 years ago