The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
Answer:
3/6 + 1/3
Step-by-step explanation:
20/24 can be devided top and bottom by 4 which would equal 5/6, if you add 3/6 + 1/3 also equals 5/6.
Answer:
d. (x+2)/(-x²-5)
Step-by-step explanation
ƒ(x) = x + 2/(2x²)
The function is undefined when x = 0.
b. ƒ(x) = (2x + 4)/(3x + 3)
The function is undefined when 3x + 3 = 0, i.e., when x = -1.
c. ƒ(x) = (6x - 5)/(x² - 7)
The function is undefined when x² - 7 = 0, i.e., when x = √7.
d. ƒ(x) = (x+2)/(-x²-5) = -(x+2)/(x² + 5)
The function would be undefined if x² + 5 = 0, i.e., if x² = -5. However, the square of a real number cannot be negative.
This function has no excluded values.
<h3>
Answer: C. 13</h3>
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Explanation:
In general if we have these two vectors
u = (a,b)
v = (c,d)
Then the dot product of them is
u dot v = a*c + b*d
We multiply the corresponding coordinates, then add up the products.
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In this case,
u = (3,2)
v = (1,5)
u dot v = 3*1+2*5
u dot v = 3 + 10
u dot v = 13
Hey there!
We can just multiply his hourly wage
by 5 to get our answer of 37.5.
Hope this helps!
