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kotykmax [81]
3 years ago
9

If (x) = x/2 -3 and g(x) = 3 x 2 + x - 6 , find (f+g) (x)

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0
I believe it’s -12x but I may be wrong I hope this helped!
dolphi86 [110]3 years ago
5 0

Answer:

(f + g)(x) = ( \frac{x}{2}  - 3) + (3 {x}^{2}  + x - 6) \\  \\  = 3 {x}^{2}  +  (\frac{x + 2x}{2} ) - 9 \\  \\  = 3 {x }^{2}  +  \frac{3x}{2}  - 9 \\  \\

I hope I helped you^_^

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Step-by-step explanation:

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ioda

Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)

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