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kondaur [170]
3 years ago
6

The table shows the annual consumption of cheese per person in the United States for selected years in the 20th century. Let x =

number of years since 1900, and y = pounds per person. What cubic model best fits this data? YearPounds Consumed. 19021.959. 19246.373. 19467.29. 198215.817. A. y = 0.00989x3 - 0.0000872x2 + 1.192x + 0.403. B. y = -0.0000872x3 + 0.00989x2 - 0.403x - 1.192. C. y = -0.0000872x3 - 0.00989x2 - 0.403x + 1.192. D. y = 0.0000872x3 - 0.00989x2 + 0.403x + 1.192
Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0
To see what model best represents this data we have to plug in the values for x and y:
Model D :
x = 2, y = 1.959
y = 0.0000872 · 2³ - 0.00989 · 2² + 0.403 · 2 + 1.192 = 1.968
....   ...
x = 82,  y = 15.817
y = 0.000873 · 82³ - 0.00989 · 82² + 0.403 · 82 + 1.192 = 15.818
Answer:
D ) y = 0.0000872 x² - 0.00989 x² + 0.403 x + 1.192
 
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Let X represent the time it takes from when someone enters the line for a roller coaster until they exit on the other side. Cons
Yuri [45]

Answer:

a. E(x) = 3.730

b. c = 3.8475

c. 0.4308

Step-by-step explanation:

a.

Given

0 x < 3

F(x) = (x-3)/1.13, 3 < x < 4.13

1 x > 4.13

Calculating E(x)

First, we'll calculate the pdf, f(x).

f(x) is the derivative of F(x)

So, if F(x) = (x-3)/1.13

f(x) = F'(x) = 1/1.13, 3 < x < 4.13

E(x) is the integral of xf(x)

xf(x) = x * 1/1.3 = x/1.3

Integrating x/1.3

E(x) = x²/(2*1.13)

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E(x) = (4.13²-3²)/2.16

E(x) = 3.730046296296296

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b.

What is the value c such that P(X < c) = 0.75

First, we'll solve F(c)

F(c) = P(x<c)

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c.

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Here we'll solve for

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Answer:

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Step-by-step explanation:

Given:

Sequence = 685+678+671+664+...+6

Find:

Sum of the sequence (Sn)

Computation:

a = 685

d = 678 - 985 = -7

an = 6

an = a+(n-1)d

6 = 685+(n-1)(-7)

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Sum of the sequence (Sn) = (n/2)[a+an]

Sum of the sequence (Sn) = (98/2)[685+6]

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