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marusya05 [52]
3 years ago
5

Assume that hybridization experiments are conducted with peas having the property that for​ offspring, there is a 0.75 probabili

ty that a pea has green pods. Assume that the offspring peas are randomly selected in groups of 18. Complete parts​ (a) through​ (c) below. a. Find the mean and the standard deviation for the numbers of peas with green pods in the groups of 18. The value of the mean is muequals nothing peas. ​(Type an integer or a decimal. Do not​ round.) The value of the standard deviation is sigmaequals nothing peas. ​(Round to one decimal place as​ needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of nothing peas or fewer are significantly low. ​(Round to one decimal place as​ needed.) Values of nothing peas or greater are significantly high. ​(Round to one decimal place as​ needed.) c. Is a result of 2 peas with green pods a result that is significantly​ low? Why or why​ not? The result ▼ is not is significantly​ low, because 2 peas with green pods is ▼ equal to greater than less than nothing peas. ​(Round to one decimal place as​ needed.)
Mathematics
1 answer:
zzz [600]3 years ago
8 0

Question is not well presented

Assume that hybridization

experiments are conducted with peas having the property that for offspring, there is

a 0. 75 probability that a pea has green pods (as in one of Mendel's famous experiments).

Assume that offspring peas are randomly selected in groups of 18. Use the range rule of thumb to find the values separating results that are significantly low or significantly high.

Answer:

Values below 9.826 (or equal) are significantly low

Values above 17.174 (or equal) are significantly high

Step-by-step explanation:

First, we Calculate the mean.

Mean = np where n = 18, p = 0.75

Mean = 18 * 0.75

Mean = 13.5

Then we Calculate the standard deviation

S = √npq where q = 1-0?75 = 0.25

S = √13.5 * 0.25

S = 1.837

The range rule of thumb tells us that the usual range of values is within 2 of the mean and Standard deviation.

i.e.

Mean - 2(s), Mean + 2(s)

13.5 - 2(1.837), 13.5 + 2(1.837)

9.826, 17.174

Values below 9.826 (or equal) are significantly low

Values above 17.174 (or equal) are significantly high

...

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