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JulijaS [17]
3 years ago
8

Find the area of the following figure. Round to the nearest tenth

Mathematics
2 answers:
UkoKoshka [18]3 years ago
6 0

Answer:

27yd

Step-by-step explanation:

7 times 7.7 = 53.9

53.9/2 = 26.95 rounded = 27

poizon [28]3 years ago
4 0

Answer:

27.0yd^2 (nearest tenth)

Step-by-step explanation:

area of triangle = 1/2 x base x height

A = 1/2 x 7.7 x 7

A = 26.95

A = 27.0 (nearest tenth)

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If y varies inversely as x and y = 9 when x = 4, find y when x = 6.
Rudiy27

Answer: x

=

6

Explanation:

the initial statement is

x

∝

1

y

to convert to an equation multiply by k the constant

of variation

⇒

x

=

k

×

1

y

=

k

y

to find k use the given condition

x

=

4

when

y

=

9

x

=

k

y

⇒

k

=

x

y

=

4

×

9

=

36

equation is

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

x

=

36

y

2

2

∣

∣

∣

−−−−−−−−−−−−

when

y

=

6

then

x

=

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6

=

6

Step-by-step explanation:

3 0
3 years ago
HELP please and explain
jonny [76]
(x3)(x4) is x7 because when you have a problem like that, you have to ADD your exponents.

-(m4)3 is -m12 since you're multiplying them.

(z3)5 is z15

y4 x y5 is y9

thats all i know of. hope it helps cx
7 0
3 years ago
Read 2 more answers
What is 1^∞ equal to?
Alex Ar [27]
The result is undefined. 
7 0
3 years ago
A cardboard sheet is cut in the shape of a triangle, with vertices at (0,0), (20,0), and (3,4) units. the thickness of the sheet
kenny6666 [7]
This problem can be solved in two ways, the long way, or the short way.

1. The long way
We know that the base of the triangle is along the x-axis, and the length of the base is 20.
The centre of mass is located at 2/3 of the distance from vertex (3,4) along the median, which cuts the base at (10,0).
Therefore the centre of mass is located at
x=3+(10-3)*2/3=23/3
y=4/3

2. The short way
It turns out that the centre of mass of a triangle sheet is located at the mean of the coordinates of the three vertices, i.e.
CG=((0+20+3)/3, (0+0+4)/3)=(23/3, 4/3)  as before.
6 0
3 years ago
What theorem states that if two sides and the included angle of one triangle are congruent to the corresponding parts of another
lianna [129]

The given statement is proved by side-angle-side (SAS) theorem.

Yes, if two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle the triangles are congruent.

The statement is proved by SAS theorem

<u>Side-Angle-Side (SAS) theorem: </u>

The triangles are congruent if two sides and the included angle of one triangle are equivalent to two sides and the included angle of another triangle.

Hence, The given statement is proved by side-angle-side (SAS) theorem.

To read more about Angles

brainly.com/question/22472034

#SPJ4

7 0
1 year ago
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