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JulijaS [17]
3 years ago
8

Find the area of the following figure. Round to the nearest tenth

Mathematics
2 answers:
UkoKoshka [18]3 years ago
6 0

Answer:

27yd

Step-by-step explanation:

7 times 7.7 = 53.9

53.9/2 = 26.95 rounded = 27

poizon [28]3 years ago
4 0

Answer:

27.0yd^2 (nearest tenth)

Step-by-step explanation:

area of triangle = 1/2 x base x height

A = 1/2 x 7.7 x 7

A = 26.95

A = 27.0 (nearest tenth)

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7 1/3 hope this helps!
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3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
there are 18 boys and 12 girl in math class. what is the ratio of girls to total students. A. 18:30 B. 12:30 C. 30:12 D. 30:18 2
zmey [24]

Answer:

1.  B

2. B and C

3.C

4.B the answer is 238 but i guess the rounded

Step-by-step explanation:

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3 years ago
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Akimi4 [234]
The amount of income tax in dollars and cents is $3,895.38
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GIVING BRAINLIEST!!!!!!PLS HELP :((
dexar [7]

Answer:

Circle A - 1 right angle

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Step-by-step explanation:

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3 years ago
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