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Arisa [49]
2 years ago
11

II. Direction: Rewrite using exponent.

Mathematics
2 answers:
skad [1K]2 years ago
8 0

\huge\text{Hey there!}

\huge\textbf{Question \#6}\\\mathsf{8\times8\times8\times 8}\\\mathsf{= 64\times64}\\\mathsf{= 4,096}\\\mathsf{\bold{8^4} = 4,096}\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{8^4}}}\huge\checkmark

\huge\textbf{Question \#7}\\\mathsf{20\times20\times20}\\\mathsf{= 400\times20}\\\mathsf{= 8,000}\\\mathsf{\bold{20^3} = 8,000}\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{20^3}}}

\huge\textbf{Question \#8}\\\mathsf{17\times17\times17\times17\times17\times17\times17\times17}\\\mathsf{= 289\times289\times289\times289}\\\mathsf{= 83,521\times83,521}\\\mathsf{= 6,975,757,441}\\\mathsf{\bold{17^8} = 6,975,757,441}\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{17^8}}}\huge\checkmark

\huge\textbf{Question \#9}\\\mathsf{245\times245\times245\times245\times245}\\\mathsf{= 60,025\times60,025\times245}\\\mathsf{= 3,603,000,625\times245}\\\mathsf{= 882,735,153,125}\\\mathsf{\bold{245^5} = 882,735,153,125}\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{245^5}}}\huge\checkmark

\huge\textbf{Question \#10}\\\mathsf{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\\mathsf{= 4\times4\times4\times4\times4}\\\mathsf{= 16\times16\times4}\\\mathsf{= 256\times4}\\\mathsf{= 1,024}\\\mathsf{\bold{2^{10}}= 1,024}\\\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{2^{10}}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

Reil [10]2 years ago
4 0

Answer:

6.) 8^4
7.) 20^3
8.) 17^8
9.) 245^5
10.) 2^10

Step-by-step explanation:

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vladimir1956 [14]

Answer:

64

Step-by-step explanation:

If you do the work:

1) Start with the whole numbers

20 x 3 = 60

2) Move to multiplying fractions

20 x 1/5

2a) To do this, start by turning the whole number into a fraction

<u>20</u> x <u>1</u>

1       5

2b) Cross-multply

<u>20</u> x <u>1</u> = <u>20</u>

1    x 5 = 5

2c) Divide

20/5 = 4

3) Add products

60 + 4 = <u><em>64</em></u>

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3 years ago
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Turn y=6x-5 (explicit) into a recursive equation
worty [1.4K]

Answer:

a_1=1\\a_n=a_{n-1}+6

Step-by-step explanation:

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6 0
2 years ago
Find all the zeros of the equation 12x^2-64=-x^4
Natalija [7]

Answer: all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

Step-by-step explanation:

Since we  have given that

12x^2-64=-x^4\\\\x^4+12x^2-64=0

We need to find the zeroes of the above equation.

So, we will use  "Split the middle terms" :

x^4+12x^2-64=0\\\\x^4+16x^2-4x^2-64=0\\\\x^2(x^2-16)-4(x^2-16)=0\\\\(x^2-4)(x^2-16)=0\\\\x^2-4=0\ or\ x^2-16=0\\\\\text{ "Using }a^2-b^2=(a+b)(a-b)"\\\\x^2-4=x^2-2^2=(x-2)(x+2)\\\\x^2-16=x^2-4^2=(x+4)(x-4)

So, all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

7 0
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