Answer:
<h3>72 units</h3>
Step-by-step explanation:
Given D,E, and F are collinear points and E is between D and F, then the expression DE + EF = DF.... 1 is true
If DE is six times the length of EF, then;
DE = 6DF
DF = DE/6 .....2
Substitute equation 2 into 1;
DE + EF = DF
DE + DE/6 = DF
find the LCM
(6DE+DE)/6 = DF
cross multiply
6DE+DE = 6DF
7DE = 6DF
Given DF = 84units
7DE = 6(84)
7DE = 504
Divide both sides by 7
7DE/7 = 504/7
DE = 72
Hence the length of segment DE is 72units
This sounds like a very poor business model right from the beginning.
The mine continuously operates at a loss, and it has nothing to sell.
If it uses 14 tons an hour just to keep running, and it produces 2 tons
an hour, then it doesn't take a business genius to point out that this
operation is rapidly digging itself straight into the ground.
I'm guessing that there was a major mistake made during the copying
of the problem.
Answer:
B, E and F
Step-by-step explanation:
This graph is a log which has an asymptote. This means the function does not cross it and does not have in its domain certain numbers. The asymptote is at -2. This means the domain is greater than -2.
The range is the y-values. With no restrictions here, the function includes all numbers.
This means B, E, and F are true.
Answer:
5 games
Step-by-step explanation:
15x + 10 = 85
- 10 = - 10
15x = 75
/15 = /15
x = 5
