Part A consists of 4 true false questions, Part B consists of 6 multiple-choice questions with one correct answer out of five, and Part C consists of 5 multiple-choice questions with one correct answer out of six.

i.e. 2 ways to answer each question in Part A.

For 4 questions, Number of ways to answer Part A = $2^4$

5 ways to answer each question in Part B.

For 6 questions, Number of ways to answer Part B = $5^6$

6 ways to answer each question in Part C.

For 5 questions, Number of ways to answer Part C = $6^5$

Now, the number of ways to completed answer sheets are possible :_

$2^4\times5^6+2^4\times6^5\\\\=2^4(5^6+6^5)\\\\=16(15625+7776)\\\\=16(23401)=374416$

Hence, the number of ways to completed answer sheets are possible = 374416

8 0

3 years ago

Solve this problem please

sasho [114]

1.0465 is what I got.

7 0

3 years ago

Read 2 more answers

Sophia exchanged 1,000 US dollars for the south African currency. the exchange rate was 7.15 rand to $1.00.

mel-nik [20]

1 / 7.15 = 1000 / x......$ 1 to 7.15 rand = $ 1000 to x rand
cross multiply because this is a proportion
(1)(x) = (7.15)(1000)
x = 7150 <=== Sophia got 7150 rand

5 0

3 years ago

Which matrix equation represents the system of equations?

Paha777 [63]

The first answer choice

8 0

2 years ago