Which statement best describes the expression 2 + 3 ÷ y?

Using the order of operations, what should be done first to evaluate (-2)^3 + 4 / (-15 + 9)(3) - 4

kogti [31]

Answer:

A. add -15 and 9

Step-by-step explanation:

We follow the PEMDAS rule as the order of operations to evaluate expressions.

P-Parenthesis

E-Exponents

M-Multiplication

D-Division

A-Addition

S-Subtraction

Given expression : $(-2)^3+4\div(-15+9)(3)-4$

In order to evaluate the expression, the first step would be to do the parenthesis operations which requires to add -15 and 9.

7 0

4 years ago

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Find the area of the figure and type your result in the empty box. 3 m 2 m 4 m

marshall27 [118]

Answer:

14m^2

Step-by-step explanation:

area of triangle = 1/2bh

= 1/2(3)(4) = 6

area of rectangle = bw

=(4)(2) = 8

6+8 = 14

8 0

3 years ago

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Find the potential solution to the equation log4(2 – x) = log4(–5x – 18).

NNADVOKAT [17]

Log₄(2 – x) = log₄(–5x – 18).

Since the logs have the same basis (4) & are equal then:

(2 – x) = (–5x – 18). . Now solve for x & you will find x = -5

4 0

3 years ago

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Factor the Polynomial by solving x^2 + bx + c = 0. m^2 - mv - 56v^2

marissa [1.9K]

Factor the Polynomial by solving x^2 + bx + c = 0.

m^2 - mv - 56v^2

Factor by grouping.

(m−8v)(m+7v).

x^2 + bx + c = 0

$x=\frac{-a+\sqrt{a^{2-4c} } }{2} , x=\frac{-a-\sqrt{a^{2-4c} } }{2}$

7 0

3 years ago

What is an equation of the line that passes through the points (-6, -2) and

den301095 [7]

Answer:

The equation of line is: $\mathbf{4x-3y=-18}$

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?

The equation of line in slope-intercept form is: $y=mx+b$

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=-6,y_1=-2, x_2=-3, y_2=2$

Putting values and finding slope

$Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}$

So, we get slope: $m=\frac{4}{3}$

Finding y-intercept

Using point (-6,-2) and slope $m=\frac{4}{3}$ we can find y-intercept

$y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6$

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope $m=\frac{4}{3}$ and y-intercept b = 6 is

$y=mx+b\\y=\frac{4}{3}x+6$

Now transforming in fully reduced form:

$y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18$

So, the equation of line is: $\mathbf{4x-3y=-18}$

6 0

3 years ago