Answer:it is going to be $52.77
Step-by-step explanation:
The volume of the gallon is 6000 gallon
the rate of water flow per min is f(t)=300t^2
a] amount of water that flowed in the first 7 minutes=7/60 hours will be:
f(7)=300(7/60)^2
solving the above we get
f(7)=7/12 gallons
b] The time taken for the tank to be empty will be as follows:
amount of water that will flow out for the tank to be empty will be 6000 gallons
thus,
6000=300t^2
this can be simplified to
20=t^2
t^2-20=0
solving this we get:
t=-2√5 or 2√5
the time taken for the tank to be empty will be t=2√5 hours=5.4721 hours
Given:
The area model.
To find:
The area as a sum and area as a product.
Solution:
The four terms of the area model are 
.
The area as a sum is the sum of all the terms of given area model.
Area as a sum = 
= 
The area as a product is the factor form of sum of all the terms of given area model.
Area as a product =
= 
= 
Therefore, the area as a sum is and the area as a product is .
Answer:
Step-by-step explanation:
Given:
Games:
0
0
1
1
2
2
3
5
5
5
6
8
8
A.
Median is the middle value after the ste of values are arranged in ascending order, M which is the 7th value = 3
B.
Median increased by 2, M + 2
Therefore, new Median = 5
This means that the 2 runs are less than the previous median, 3 or greater than the new median, 5.
Possible pairs:
1, 2 or 6, 8
C.
Median can be 2.5 when the total number of runs scored are even numbers, therefore if the middle numbers are 2 and 3. In this case a number greater than or equal to 2;
The median = (2 + 3)/2
= 2.5
D.
Range is the difference between the highest value of runs scored to the lowest value of runs. In the data given above, range = 8 - 0
= 8.
It is possible to play 2 more games and no change in the range, 8 if the value of the 2 games (or 1 game) is/are greater than 0, the lowest value of runs scored and/or less than 8, which is the greatest value of runs scored.
Answer:
y = 120
Step-by-step explanation:
If y = 32 when x = 8, then <em>y</em> is 4 times the number of <em>x</em>. If x = 30, then (4)30 = 120.
