Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
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Answer:
The answer is 77.7777 or 77.8 if to round to tenth.
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
Mode = modal class (Recurring)
The number/value that appears the most which in this case is 18 because it can be seen twice.
Answer:
Part A: 1/(2^6) or 1/64
Part B: 1
Step-by-step explanation:
For both parts, you have to keep in mind that a number multiplied by its reciprocal will equal one. For Part B specifically, remember that any number (excluding one) to the 0th power is equal to one