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3 years ago

HELP ASAP!!

Mathematics

1 answer:

Alex3 years ago

4 0

Answer:

Part A: 1/(2^6) or 1/64

Part B: 1

Step-by-step explanation:

For both parts, you have to keep in mind that a number multiplied by its reciprocal will equal one. For Part B specifically, remember that any number (excluding one) to the 0th power is equal to one

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The cross section of a hopper for containing balls is shown.

svp [43]

ANSWER

$14 \: ft$

EXPLANATION

Let the top of the hopper be

$l \: ft$

Then, by the cosine rule,

${l}^{2} = {13}^{2} + {15}^{2} - 2(15)(13) \cos(59.5 \degree)$

We evaluate to get,

${l}^{2} = 169 + 225 - 390\cos(59.5 \degree)$

${l}^{2} = 394 - 197.94$

${l}^{2} = 196.06$
Take positive square root of both sides to get,

$l = \sqrt{196.06}$

$l = 14.00$

3 0

3 years ago

Read 2 more answers

How do I solve this problem step by step?

Salsk061 [2.6K]

Unlocking pm....................................

7 0

3 years ago

There are a total of 64 students in a drama club and a yearbook club. The drama club has 14 more students than the yearbook club

Scorpion4ik [409]

L=x which repents students

7 0

4 years ago

Line L is NOT a function. The equation of line L could be A) x + 3 = 0. B) y + 3 = 0. C) y + 3x = 0. D) x + 3y = 0.

Damm [24]

Answer:

None of the above.

Step-by-step explanation:

All of these are functions. For each input of x, there is only one output of y. Therefore, they are all functions.

7 0

3 years ago

Read 2 more answers

Please Help ASAP

Orlov [11]

The C(x) equation is a parabola with a squared "x" and a positive leading term coefficient, meaning, is a vertical parabola and it opens upwards

the lowest point, or lowest cost value, it reaches, is the U-turn point, or vertex

$\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{llccll}
y = &{{ 1}}x^2&{{ -320}}x&{{ +40052}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$

so, the lowest cost is at $\bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}$

8 0

4 years ago