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Molodets [167]
3 years ago
11

I have one more question I can figure out how to get the answer via the calculator but I'm not sure how I got there

Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0

Answer:

43.6 * 2.94 = 436/10 * 294/100 = (436 * 294)/1000 = 128184/1000 = 128.184

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Points E, F, and D are on circle C, and angle G measures 60°. The measure of arc EF equals the measure of arc FD.
galben [10]

Answer:

∠EFD ≅ ∠EGD ⇒ A

Arc ED ≅ arc FD ⇒ C

m arc FD = 120° ⇒ E

Step-by-step explanation:

Let us revise some facts

  1. Equal chords subtended equal arcs
  2. The measure of an inscribed angle is one-half the measure of the central angle which subtended by the same arc
  3. The measure of a central angle is equal to the measure of its subtended arc
  4. If one angle of an isosceles triangle measure 60° then the triangle is equilateral
  5. The sum of the measures of the interior angles of any quadrilateral is 360°

In the quadrilateral  CDGE

∵ m∠G = 60°

∵ m∠GDC = m∠GEC = 90°

- By using the 5th rule above

∴ m∠G + m∠GDC + m∠DCE + m∠GEC = 360°

∴ 60 + 90 + m∠DCE + 90 = 360

∴ 240 + m∠DCE = 360

- Subtract 240 from both sides

∵ m∠DCE = 120°

In circle C

∵ ∠DCE is a central angle subtended by arc DE

∵ ∠DFE is an inscribed angle subtended by arc DE

- By using the 2nd rule above

∴ m∠DFE = \frac{1}{2} m∠∠DCE

∵ m∠DCE = 120°

∴ m∠DFE = \frac{1}{2} (120)

∴ m∠DFE = 60°

- That means ∠EFD ≅ ∠EGD because their measure is 60°

∴ ∠EFD ≅ ∠EGD

In Δ EFD

∵ EF = FD

∵ m∠DFE = 60°

- By using the 4th rule above

∴ Δ EFD is an equilateral triangle

∴ ED = FD = FE

In circle C

∵ Side ED subtended by arc ED

∵ Side FD subtended by FD

∵ Side ED ≅ side FD ⇒ proved

- By using the 1st rule above

∴ Arc ED ≅ arc FD

∵ m∠ECD = 120°

∵ ∠ECD is a central angle subtended by arc ED

- By using the 3rd rule above

∴ m∠ECD = m arc ED

∴ m of arc ED = 120°

∵ Arc ED ≅ arc FD

∴ m arc ED = m arc FD

∴ m arc FD = 120°

5 0
3 years ago
Read 2 more answers
A roulette wheel has 38 slots around the rim. the first 36 slots are numbers from 1 to 36. half of these 36 slots are​ red, and
pshichka [43]

Answer:

15 or 16 times

Step-by-step explanation:

6 0
3 years ago
The length of sides of triangular fields are 10m, 24m and 26m. A farmer grows flowers in this field. If 5kg flowers can be obtai
Ostrovityanka [42]

Answer:

Area: 120m²

Flowers: 600kg

Step-by-step explanation:

we can use Heron's formula to solve for the area.

Heron's formula:

Area of triangle = \sqrt{ s(s-a)(s-b)(s-c)}

s = 1/2 (a+b+c)

s = 1/2 (10 +24+26)

s = 30

Area of triangle

=\sqrt{30(30-10)(30-24)(30-26)} \\=120m^{2}

Since every 1 m² of area can grow 5kg of flowers,

the yield of flowers will be:

120 x 5

=600kg

7 0
3 years ago
Edgar Anderson earns $300 a week plus a 15% commission on all sales over $1,000. If Mr. Anderson's sales for one week are $2,500
denis23 [38]
It would be
D.675
⇒Leave A Thanks! :)
7 0
3 years ago
A chocolate bar measures 30 mm wide, 70 mm long, and (or 4.5) mm high. Will's Wrapping Company is making a wrapper to cover the
KiRa [710]

Hey there! I'm happy to help!

First, let's find the area of the top of the bar.

30×70=2100

This is the same as the bottom of the bar, so we have another 2100 mm, giving us 4200 in total.

Now we want to find the two long sides. This is 70×4.5, which is 315. Since there are two of these sides, we have another 315, giving us 630 in total there.

Now we have the short sides.

30×4.5=135

135×2=270

Now, we add up all of these measurements.

4200+630+270=5100

Therefore, Will's Wrapping Company will need 5100 mm² of paper to make their wrapper.

Have a wonderful day! :D

8 0
3 years ago
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