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Zolol [24]
3 years ago
15

A roulette wheel has 38 slots around the rim. the first 36 slots are numbers from 1 to 36. half of these 36 slots are​ red, and

the other half are black. the remaining 2 slots are numbered 0 and 00 and are green. if the roulette wheel is spun 152 times predict about how many times the ball will land on 17 or 20
Mathematics
1 answer:
pshichka [43]3 years ago
6 0

Answer:

15 or 16 times

Step-by-step explanation:

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Given the equation y = 3x − 4, what is the value of x when y = 5? A) 3 B) 6 C) 9 D) 12
timurjin [86]

Answer:

3

Step-by-step explanation:

the equation would be 5 = 3(3) - 4

which is 9 - 4 = 5

7 0
3 years ago
กิน
-BARSIC- [3]
It’s A because the hundreds place is 5 the tens is 8 which is one less then 9 and the ones is 9 which is more then 8
5 0
3 years ago
Find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8 ,10,12 and 30.
Nookie1986 [14]
Well, that means that it is 3 more than a common multipule of 8,10,12, and 30
find the lcm

8=2*2*2
10=2*5
12=2*2*3
30=2*3*5
lcm=2*2*2*3*5=120
times it by 2 to get it between 200 and 500
240
add 3
243 is da number
5 0
3 years ago
Read 2 more answers
A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class
KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                   T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of seniors who skipped their classes = \frac{77}{2521}

           n = sample of classes = 2521

So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

                               =  3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, <u>the z table gives critical value of 2.3263 for right-tailed test</u>. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0
3 years ago
HELPPP PLEASEEEEEEEEE
liubo4ka [24]
Y=4x+7

So 4 is the rate of change because if you solve for y, x is the rate of change
4 0
3 years ago
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