Ask question

Ask question

All categories

2 years ago

15

The radius of a circle is 7 cm. Find its area to the nearest tenth. (Please help due in an hour)

1 answer:

Zepler [3.9K]2 years ago

7 0

<h2><u>153.9 square centimeters</u> is the correct answer!</h2><h3 /><h3>A = r²(π)</h3><h3>(Assuming pi equals 3.14)</h3><h3 /><h3>7 x 7 = 49</h3><h3>49 x 3.14 = 153.86</h3><h3 /><h3>153.86 rounds to 153.9</h3><h3 /><h3><em>Please let me know if I am wrong.</em></h3>

You might be interested in

=<br> = 70<br> 7<br> 7² 78<br> 74<br> a =<br> a<br> 79<br> 74<br> b=

weqwewe [10]

I need points so imma answer

7 0

2 years ago

Which of the following statements about length of investment is correct? a. Bonds tend to be better long-term investments than s

Vladimir79 [104]

B) <span>Stocks tend to be better long-term investments than bonds because bonds do not have the same growth potential that stocks do.</span>

3 0

3 years ago

Read 2 more answers

ASAP Which absolute value function, when graphed, will be wider than the graph of the parent function, f(x) = |x|?

Natalija [7]

Is there something missing on the third option? None of the other options are wider

4 0

3 years ago

Read 2 more answers

In a certain Algebra 2 class of 25 students, 13 of them play basketball and 11 of them play baseball. There are 4 students who p

Flauer [41]

Answer:

$\frac{4}{5}$

Step-by-step explanation:

Given: There are 2 classes of 25 students.

13 play basketball

11 play baseball.

4 play neither of sports.

Lets assume basketball as "a" and baseball as "b".

We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)

As given total number of student is 25

Now, subtituting the values in the formula.

⇒P(a∪b)= $\frac{13}{25} +\frac{11}{25} -\frac{4}{25}$

taking LCD as 25 to solve.

⇒P(a∪b)= $\frac{13\times 1+11\times 1-4\times 1}{25} = \frac{20}{25}$

∴ P(a∪b)= $\frac{4}{5}$

Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is $\frac{4}{5}$ .

6 0

3 years ago

Let U = {5, 10, 15, 20, 25, 30, 35, 40, 45, 50} A = {5, 10, 15, 20, 25} B = {25, 30, 35, 40, 45} C = {10, 20, 30, 40, 50} Find A

Dima020 [189]

Answer:

A∪B = {5, 10, 15, 20, 25, 30, 35, 40, 45}

Step-by-step explanation:

A = {5, 10, 15, 20, 25}

B = {25, 30, 35, 40, 45}

Find A∪B

There are 5 elements in set A

There are 5 elements in set B

A∪B is the combination of all the elements in set A and set B without repeating any

A∪B = {5, 10, 15, 20, 25, 30, 35, 40, 45}

A∪B has 9 elements in it

A ⋂ B = {25}

6 0

3 years ago