Answer
given,
![f(x) = 2 x^{1/5}](https://tex.z-dn.net/?f=f%28x%29%20%3D%202%20x%5E%7B1%2F5%7D)
interval = [-32, 32]
differentiating the given equation
![f'(x) = \dfrac{d}{dx}(2 x^{1/5})](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%5Cdfrac%7Bd%7D%7Bdx%7D%282%20x%5E%7B1%2F5%7D%29)
![f'(x) = \dfrac{2}{5x^{4/5}}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%5Cdfrac%7B2%7D%7B5x%5E%7B4%2F5%7D%7D)
hence, the above solution is not defined at x = 0
and x = 0 lie in the given interval i.e. [-32, 32]
so, at x = 0 the function is not differentiable.
Hence, mean value theorem does not apply to the given function.
Step-by-step explanation:
In,
Question 2 I have already answered,
Q. 3)
<h3>
<em><u>Given</u></em><em><u> </u></em><em><u>Question</u></em><em><u>:</u></em></h3>
![\frac{ {c}^{2} }{d}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7Bc%7D%5E%7B2%7D%20%7D%7Bd%7D%20)
<em><u>Given</u></em><em><u> </u></em><em><u>values</u></em><em><u>:</u></em><em><u>-</u></em>
c = 6 , d = 3
<em><u>By</u></em><em><u> </u></em><em><u>putting</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>values</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>question</u></em><em><u>, </u></em>
![\frac{ {6}^{2} }{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B6%7D%5E%7B2%7D%20%7D%7B3%7D%20)
![= \frac{36}{3}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B36%7D%7B3%7D%20)
= <em><u>12 (Ans)</u></em>
The answer to this is negative
There should be 24 turtles
Answer:
40.92
Step-by-step explanation:
hope this helps