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Norma-Jean [14]
3 years ago
11

What is the solution to the following equation? x^2-3x-10=0

Mathematics
2 answers:
LiRa [457]3 years ago
7 0

Answer:

A= x=5 or x=-2

Step-by-step explanation:

x^2-3x-10=0

Factor

What 2 numbers multiply together to give you -10 and add together to give you -3

-5*2 = -10

-5+2 = -3

(x-5) (x+2) =0

Using the zero product property

x-5 =0         x+2 =0

x-5+5=0+5    x+2-2=0-2

x=5   x=-2

Kitty [74]3 years ago
3 0

x^2 - 3x -10 = 0

Find two numbers when added together = -3 and when multiplied = -10

-5 + 2 = -3

-5 * 2 = -10

Now write the factored form of the equation:(x-5) (x+2) = 0

Solve for each x so that the equation = 0:

5 -5 = 0

-2 + 2 = 0

So X = -2 or 5

The answer is A.

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Answer:

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The measure of an angle is 49°. what is the measure of a complementary angle?
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Please help me I need help please​
MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

x^2+(p-3)y^2-4x+6y-16=0

<u>Standard equation of a circle:</u>

(x-a)^2+(y-b)^2=r^2

(where (a,b) is the centre of the circle, and r is the radius)

If you expand this equation, you will see that the coefficient of y^2 is always one.

Therefore, p-3=1

\implies p=1+3=4

<u>Additional information</u>

To rewrite the given equation in the standard form:

\implies x^2+y^2-4x+6y-16=0

\implies x^2-4x+y^2+6y=16

\implies (x-2)^2-4+(y+3)^2-9=16

\implies (x-2)^2+(y+3)^2=16+4+9

\implies (x-2)^2+(y+3)^2=29

So this is a circle with centre (2, -3) and radius √29

3 0
2 years ago
5. Evie and sophia are planning a cement patio by their swimming pool. A contractor says the cement will weigh 61⁄3 tons. How ma
lana [24]
Divide 6 1/3 by 3/4
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then multiply 76/12 by the reciprocal of 9/12 (which is 12/9)
cross reduce, you get 76/9
convert back to a mixed number
76/9 --> 8 4/9
it would take 9 loads
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3 years ago
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