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Rudiy27
2 years ago
12

Rachel and three friends were going to the movies. Each ticket cost $10.50 and then they bought 2 popcorns at $3.50 each, and th

ey each
bought their own soda at $2.75 each. How much money did they spend total for their trip to the movies?
If they decide to split the
bill, how much will they each pay?
Mathematics
1 answer:
nadezda [96]2 years ago
8 0

total amount is $46.75 and if they split the cost it is $15.58

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Can someone please answer this for me i cant figure it out.
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<h3>Answer:</h3>

\displaystyle x^{\frac{2}{3}}

<h3>Step-by-step explanation:</h3>

The rules of exponents tell you ...

... (a^b)(a^c) = a^(b+c) . . . . . . applies inside parentheses

... (a^b)^c = a^(b·c) . . . . . . . . applies to the overall expression

The Order of Operations tells you to evaluate inside parentheses first. Doing that, you have ...

... x^(4/3)·x^(2/3) = x^((4+2)/3) = x^2

Now, you have ...

... (x^2)^(1/3)

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8208 total tickets / 12 concerts =
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Use a standard normal table to find the positive critical value that corresponds to a right tail area of 0.0250.025​, rounding t
IRINA_888 [86]
Let the require value be x, then

P(z > x) = 0.025
1 - P(z < x) = 0.025
P(z < x) = 1 - 0.025 = 0.975
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x = 1.96

Therefore, <span>the positive critical value that corresponds to a right tail area of 0.025</span> is 1.96
4 0
3 years ago
A drug is eliminated from the body through urine. Suppose that for a dose of 10 milligrams, the amount A(t) remaining in the bod
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Answer: a - 4.512 hours

b - 1.94 hours

Step-by-step explanation:

Given,

a) A(t) = 10 (0.7)^t

To determine when 2mg is left in the body

We would have,

A(t) = 2, therefore

2 = 10(0.7)^t

0.7^t =2÷10

0.7^t = 0.2

Take the log of both sides,

Log (0.7)^t = log 0.2

t log 0.7 = log 0.2

t = log 0.2/ 0.7

t = 4.512 hours

Thus it will take 4.512 hours for 2mg to be left in the body.

b) Half life

Let A(t) = 1/2 A(0)

Thus,

1/2 A(0) = A(0)0.7^t

Divide both sides by A(0)

1/2 = 0.7^t

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Take log of both sides

Log 0.7^t = log 0.5

t log 0.7 = log 0.5

t = log 0.5/log 0.7

t = 1.94 hours

Therefore, the half life of the drug is 1.94 hours

6 0
3 years ago
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