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2 years ago

How do i find the first term of a geometric sequence when i know a3= 1/8 and a6= 1 ?

Mathematics

1 answer:

ale4655 [162]2 years ago

6 0

Answer:

Step-by-step explanation:

nth term = ar^(n-1)

a3 = 1/8; ar² = 1/8

a6 = 1; ar⁵ = 1

$ar^{2}*r^{3}=1\\\\\frac{1}{8}*r^{3}=1\\\\r^{3}=1*8\\\\r^{3}=8\\\\r^{3}=2^{3}\\\\r=2$

$ar^{2}=\frac{1}{8}\\\\a*2^{2}=\frac{1}{8}\\\\a*4=\frac{1}{8}\\\\a=\frac{1}{8*4}\\\\a=\frac{1}{32}\\\\$

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