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2 years ago

Which formula can be used to find the nth term of a geometric sequence where the first term is 8 and the common ratio is -3

Mathematics

2 answers:

kirill [66]2 years ago

8 0

Hello :
the nth term is : an= a1×q^(n-1)....... a1 = 8 and q = -3

an= 8×(-3)^(n-1)

Slav-nsk [51]2 years ago

6 0

Answer:

The answer is A.

Step-by-step explanation:

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1.2 = m - 2.5 m=? What would be the answer?

zysi [14]

Answer:

3.7

Step-by-step explanation:

1. 2 = m - 2.5

m =?

from the question simple arithmetic will be applied by simply collecting the like terms together

therefore; m = 1.2 + 2.5

m = 3.7

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2 years ago

Jill sold 478 out of 520 tickets to the opening night of her theater performance. What portion of the tickets did she sell?

Arte-miy333 [17]

Answer:

write your answer as a decimal, then round

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2 years ago

You want $5000 4 years from nowfor a down payment for a car. How much money must be deposited monetly into an account earning 4.

timama [110]

Answer:

$95.5090 must be deposited monthly

Step-by-step explanation:

From the information given:

The annual interest rate (r) = 4.2% = 0.042

Let assume that an amount Y is deposited, then after one month, it will increase to:

$Y ( 1+ \dfrac{0.042}{12})$

The total amount after 4 years will be:

$= Y ( 1+ \dfrac{0.042}{12})^{48}+Y ( 1+ \dfrac{0.042}{12})^{47} +Y ( 1+ \dfrac{0.042}{12})^{46} +...+ Y ( 1+ \dfrac{0.042}{12})$

$= Y ( 1.0035)^{48}+Y ( 1.0035)^{47} +Y( 1.0035)^{46} +...+ Y( 1.0035)$

Using the sum of a geometric progression:

$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{(1.0035-1)}$

$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{0.0035}$

The above amount is then equal to $5000

i.e

$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{0.0035} = 5000$

$Y = \dfrac{5000\times 0.0035}{(1.0035)(1.0035^{48}-1)} \\ \\ \mathbf{Y = \$95.5090}$

8 0

2 years ago

5 (x minus 6) = 2 (x + 3)?

deff fn [24]

Answer:

Step-by-step explanation:

5(x-6)=2(x+3)

multiply

5*x and 5*6. 2*x and 2*3

5x-30=2x+6

minus 5x and 2x

3x-30=6

add 30 to 6

3x=36

divide both sides by 3 and the 3x cancels so 36÷3

x=12

6 0

2 years ago

For there are 48 apples and 60 bananas and 96 oranges each basket must contain the same number of each type of frut Search inste

vaieri [72.5K]

This question is incomplete

Complete Question

For there are 48 apples and 60 bananas and 96 oranges each basket must contain the same number of each type of fruit. Find the greatest number of baskets you can have

Answer:

The greatest number of baskets you can have is 12 baskets.

And each baskets would contain:

4 apples, 5 bananas and 8 oranges

Step-by-step explanation:

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 96 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96

Then the greatest common factor is 12.

Therefore, the greatest number of baskets you can have is 12 baskets.

Each baskets would have

For apples

48 apples

48 apples / 12 baskets = 4 apples per basket

For bananas

60 bananas

60 bananas/12 baskets = 5 bananas per basket

For Oranges

96 Oranges/ 12 baskets = 8 oranges per baskets

8 0

2 years ago