Answer:
x=3,y=0
x=-1,y=0
Step-by-step explanation:
We will have to factorise to get the value of x before solving for y
Let's solve
y=x^2-2x-3
To factorise x
x^2-3x+x-3
x(x-3)+1(x-3)
(x-3)+(x+1)
x-3=0
x=3
x+1=0
x=-1
Let's substitute the value of value to get the value for y
y=x^2-2x-3
When x is 3
y=3^2-2(3)-3
y=9-6-3
y=0
When x is-1
y=(-1)^2-2(-1)-3
y=1+2-3
y=0
Therefore when x is 3,y is 0
When x is -1,y is 0
86 and 95; 8+6=14 and 9+5 also =14. The tens value for both of these numbers are also higher than their ones place.
Answer:
266 guests
Step-by-step explanation:
7 people per table and 38 tables means 7x38=266.
Brainliest always helps!
