We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3
Answer : x= -4
This type of problem, you set them equal to each other. And then solve. Don’t forget you can multiply each side by denominator to eliminate the fraction.
Work:
You start at 0 on the unit circle the cos of 0 =1, but at cos 0 there is no angle at all so there is no y value so at cos 0 y=0, 180 is the opposite direction of the starting point which is 0 so the x value of cos180= -1 but there is still no upward or downward angle ie.. y value. so the y value = 0 at 0 and 180. answer is 0
1. x - 4
x - 6|x² - 10x + 24
- (x² - 6x)
-4x + 24
- (4x + 24)
0
The answer is C.
2. A. 9x² + 12x - 3
3(x²) + 3(4x) - 3(1)
3(x² + 4x - 1)
B. 9x² + 3x - 5
Not Factored
C. 6x² + 10x - 4
2(3x²) + 2(5x) - 2(2)
2(3x² + 5x - 2)
2(3x² + 6x - x - 2)
2(3x(x) + 3x(2) - 1(x) - 1(2))
2(3x(x + 2) - 1(x + 2))
2(3x - 1)(x + 2)
D. 6x² + 7x - 6
Not Factored
The answer is C.
3. 3x³ - 4x² + 3x - 6
x + 2|3x⁴ + 2x³ - 5x² + 0x - 4
- (3x⁴ + 6x³)
-4x³ - 5x²
- (-4x³ - 8x²)
3x² + 0x
- (3x² + 6x)
-6x - 4
- (-6x - 12)
8
The answer is A.
Angle B is the linear pairs with 60°, so the size is 180-60=120°
Angle ABC is the linear pair with 120°, so the size is 180-120-60°
Angle A corresponds to angle 60°, so they are equal
Angle BAC is the linear pair with angle A and angle 70°, so 180-(60+70)=50°
Angle ACB is 180-(50+60) = 70°