Question

A stone which is dropped into a dry well hits the bottom in 2.2s how deep is the well. take g=10m/s​

Answer 1

Answer:

23.7m

Step-by-step explanation:

Given parameters:

       Time taken = 2.2s

     Acceleration due to gravity = 10m/s

Unknown:

Depth of the well  = ?

Solution:

To solve this problem, we simply apply one of the motion equations;

        S = ut + $\frac{1}{2}$ gt²

    where S = depth of the well

                u = initial velocity

                t = time taken

               g = acceleration due to gravity

 Input the parameters and solve for S;

   Note initial velocity = 0;

     S = $\frac{1}{2}$ x 9.8 x 2.2²

    S = 23.7m