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Novosadov [1.4K]
3 years ago
13

A stone which is dropped into a dry well hits the bottom in 2.2s how deep is the well. take g=10m/s​

Mathematics
1 answer:
Papessa [141]3 years ago
3 0

Answer:

23.7m

Step-by-step explanation:

Given parameters:

       Time taken = 2.2s

     Acceleration due to gravity = 10m/s

Unknown:

Depth of the well  = ?

Solution:

To solve this problem, we simply apply one of the motion equations;

        S = ut + \frac{1}{2} gt²

    where S = depth of the well

                u = initial velocity

                t = time taken

               g = acceleration due to gravity

 Input the parameters and solve for S;

   Note initial velocity = 0;

     S = \frac{1}{2} x 9.8 x 2.2²

    S = 23.7m

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Given:

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Solution:

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Using Pythagoras theorem, we get

Hyponteuse^2=Base^2+Perpendicular^2

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Divide both sides by 2.

81=(a)^2

Taking square root on both sides.

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3 years ago
Please help! Thank you if you do!
vekshin1

Answer:

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A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
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Answer:

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And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

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And the standard error would be:

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And replacing we got:

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Step-by-step explanation:

For this case we know the population deviation given by:

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And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

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