What division sentence means the same as the following subtract sentences?

What are the coordinates of the point on the directed line segment from (- 3, - 9) to (4, 5) that partitions the segment into a

kompoz [17]

Answer:

(0,-1)

Step-by-step explanation:

Let the ends of the line segments be A(-4,3) and B(5,-6).

Ratio=4:5

By the concept of cordinate geometry,

x=(mx2+nx1)/(m+n)

y=(my2+ny1)/(m+n)

where m and n is the ratio m:n.

So, here the cordinates are

x={4(5)+5(-4)}/(4+5)

x=(20–20)/9

x=0

y={4(-6)+5(3)}/9

y={-24+15}/9

y=(-9)/9

y=(-1)

Therefore the cordinates of the point that divides the given line segment in the ratio 4 : 5 is (0,-1)

:)

5 0

2 years ago

Find x, the angle of depression from the top of a lighthouse that is 152ft above water level to the waterline of a ship 868ft of

cestrela7 [59]

Answer:

$\theta = 9.93$

Step-by-step explanation:

If we draw a right angle triangle ABC,

where B is the vertex with 90 degrees.

A is the top of the lighthouse

C is the waterline of the ship.

we can write the sidelengths of this triangle.

AB = 152

BC = 868.

to find the angle of depression $(\theta)$ , all we need to find is the angle BAC and subtract it from 90 degrees.

$\theta = 90 - B\hat{A}C$

to find the angle BAC, we'll use trigonometric functions.

we don't have the hypotenuse of the triangle, and we won't be needing it either. we'll use tan

$\tan{x} = \dfrac{\text{opposite side}}{\text{adjacent side}}$

$\tan{B\hat{A}C$ } = \dfrac{BC}{AB}[/tex]

$\tan{B\hat{A}C$ } = \dfrac{868}{152}[/tex]

$B\hat{A}C = \arctan{\left(\dfrac{868}{152}\right)}$

$B\hat{A}C = 80.067$

to find the angle of depression:

$\theta = 90 - B\hat{A}C$

$\theta = 90 - 80.067$

$\theta = 9.93$

3 0

3 years ago

Can you help me solve this?

shusha [124]

Not possible, because it would come out as 4=-2 and that isn't possible

6 0

3 years ago

Read 2 more answers

The regular hexagon has a radius of 4 in.

AleksAgata [21]

$\bf \textit{area of a regular polygon}=\cfrac{1}{2}nR^2\cdot sin\left(\frac{360}{n} \right)
\\ \quad \\ \quad \\
\begin{cases}
n=\textit{number of sides in the polygon}\\
R=\textit{radius of the polygon}
\end{cases}$

so, sides= n= 6
radius = R = 4
$\bf \textit{area of a regular polygon}=\cfrac{1}{2}nR^2\cdot sin\left(\frac{360}{n} \right)
\\ \quad \\ \quad \\
\begin{cases}
n=\textit{number of sides in the polygon}\\
R=\textit{radius of the polygon}
\end{cases}
\\ \quad \\ \quad \\
\cfrac{1}{2}6\cdot 4^2\cdot sin\left(\frac{360}{6} \right)\implies 
\cfrac{1}{2}\cdot 96\cdot sin\left(60^o \right)
\\ \quad \\
48\cdot sin\left(60^o \right)$

6 0

3 years ago

Read 2 more answers

Using technology, determine the monthly payment on a 35 month loan of $28,000 at 8.1% compounded monthly. Round your answer to t

miv72 [106K]

Answer: a

Step-by-step explanation:

Took test

8 0

2 years ago