Answer:
The solution of the system of equations are the points (-2,-6) and (4,6)
Step-by-step explanation:
we have
----> equation A
----> inequality B
we know that
The solution of the system of equations is the intersection point both graphs
To graph the linear equation, find the intercepts
<em>Find the y-intercept</em>
The y-intercept is the value of y when the value of x is equal to zero
For x=0
The y-intercept is the point (0,-2)
<em>Find the x-intercept</em>
The x-intercept is the value of x when the value of y is equal to zero
For y=0
The x-intercept is the point (1,0)
Plot the intercepts to graph the linear equation and find the intersection points with the quadratic equation
The intersection points are (-2,-6) and (4,6)
see the attached figure
therefore
The solution of the system of equations are the points (-2,-6) and (4,6)
Answer:
(4, -3) reflected over the X axis is (4,3)
Step-by-step explanation:
Sometimes, as it can be positive or negative but that is dependent on where the point is located.
Answer:
Step-by-step explanation:
The Given diffrential equation can be written as follows
Solving the auxiliary equation we get
Comparing with the standard quadratic equation we get
Using the values we get the roots as
The roots are imaginary and conjugate
For a auxillary equation with roots the solution is given by
Applying values we get the solution of the equation as
....................(i)
here are constants whose values shall be obtained using the given boundary conditions y(0) = 9 ; y'(0) = 8
In equation i putting x = 0 we get
9 =
Now we have
Now y'(0) = 8
Thus we get
Solving for we get
Thus the solution becomes