Put a point H on (9, 2). Sketch a triangle out of the three points. Distance between (-2, 2) and (9, 2) is going to be 11. Distance between (9, 2) and (9, 5) is going to be 3. These correspond to the a and b of the Pythagorean Theorem
c^2=a^2+b^2
c=√11^2+3^2=√130
<span>Square root of 130 is 11.4</span>
The way you worded the question kind of confuses me but i'll try to answer.
Think of recursion like climbing a ladder; in this type of sequence you start out somewhere, usually n. So in f(n-1)+1, you take n (where you started) and "step down" once, and then step up once (which brings you back where you were). Remember PEMDAS when doing these.
Answer:
6
Step-by-step explanation:
the middle number of the given list
The area of the trapezoid is 57.5 square inches.
If you draw out the description, you will see that your trapezoid can be divided into a rectangle that is 9 x 5 and an isosceles right triangle with a base of 5 and height of 5.
Just find the areas of both and add them together.
Rectangle:
5 x 9 = 45
Triangle:
0.5 x 5 x 5 = 12.5
45 + 12.5 = 57.5
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