Answer:
that sucks but for me to help you, you have to put the question. i dont see anything
Step-by-step explanation:
TQRS is an inscribed quadrilateral.
5 x - 52° + 3 x + 40° = 180°
8 x - 12° = 180°
8 x = 180° + 12°
8 x = 192°
x = 192° : 8 = 24°
m∠ R = 3 · 24° + 40° = 112°
m∠ T = 5 · 24° - 52° = 68°
m∠ S = 360° - ( 68° + 68° + 112° ) = 112°
Answer:
m∠R, m∠S, m∠T = <span>112°, 112°, 68°.</span>
To solve the problem, we can use the angle sum of triangle,where the addition of all triangles would be equal to 180°.
In this case, 90° is already given, hence we can use the rest angles with unknown to set up equaiton:
90° + 2x + 3x = 180°
2x + 3x = 180°- 90°
5x = 90°
x = 90°/5
x = 18°
Therefore, x= 18°.
Hope it helps!
Sub j(x)=-5 into the first eq.
-5=(4/5x)+7
Add 7 to both sides
2=4/5x
Muliply both sides times 5x
10x=4
Divide both sides by 10
X=4/10
Simplify
X=2/5
Answer:
y + 6 = 2/3 (x - 2)
Step-by-step explanation:
Step 1. Find the slope
m = slope
m = change in y/change in x
m = (y2 - y1)/(x2 - x1)
points: (2, -6) & (8, -2)
m = (-2 - -6)/(8 - 2)
m = 4/6
m = 2/3
Step 2. Create the point-slope equation by using the slope and the first point
Point-slope formula: y - y1 = m(x - x1)
Where m = slope and (x1, y1) = first point
Point-slope form: y + 6 = 2/3 (x - 2)
