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1 year ago

Which shows 0.00234 written in scientific notation?

1 answer:

6 0

It’s D

the reason why is because the multiplier must be between 1 and 10
(
1
≤
x
≤
10
)
so first more your decimal there which you get:
2.34
then just count how many numbers the decimal jumped, if the decimal moved left the exponent is positive and if it moved right, as in your number, the exponent is negative

yours moved 3

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Which is equivalent to

Vanyuwa [196]

the answer is A couse divide all 5

8 0

3 years ago

.Fred is making a bouquet of carnations and roses. The carnations cost $5.25 in all. The roses cost $1.68 each. How many roses d

Vinil7 [7]

Answer:

8 roses

Step-by-step explanation:

1)18.69-5.25=13.44

because you are trying to find the cost of the roses

2)13.44/1.68=8

because you already know how much the roses cost for each rose and all together.

3 0

3 years ago

A bag of popcorn contains 945 calories and serves 7.5 people. How many calories are in each serving?

ki77a [65]

Answer:

126

Step-by-step explanation:

945÷7.5=126

I HOPE IT HELPS!

5 0

3 years ago

The points plotted below are on the graph of a polynomial. In what range of

Irina-Kira [14]

Answer:

the answer is 0 to 1 and 3 to 4

7 0

3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

3 years ago