Answer:
The quadratic x2 − 5x + 6 factors as (x − 2)(x − 3). Hence the equation x2 − 5x + 6 = 0
has solutions x = 2 and x = 3.
Similarly we can factor the cubic x3 − 6x2 + 11x − 6 as (x − 1)(x − 2)(x − 3), which enables us to show that the solutions of x3 − 6x2 + 11x − 6 = 0 are x = 1, x = 2 or x = 3. In this module we will see how to arrive at this factorisation.
Polynomials in many respects behave like whole numbers or the integers. We can add, subtract and multiply two or more polynomials together to obtain another polynomial. Just as we can divide one whole number by another, producing a quotient and remainder, we can divide one polynomial by another and obtain a quotient and remainder, which are also polynomials.
A quadratic equation of the form ax2 + bx + c has either 0, 1 or 2 solutions, depending on whether the discriminant is negative, zero or positive. The number of solutions of the this equation assisted us in drawing the graph of the quadratic function y = ax2 + bx + c. Similarly, information about the roots of a polynomial equation enables us to give a rough sketch of the corresponding polynomial function.
As well as being intrinsically interesting objects, polynomials have important applications in the real world. One such application to error-correcting codes is discussed in the Appendix to this module.
We have a right triangle. We know the hypotenuse (75 ft) and an angle of 35°. We need to find the opposite leg to the angle of 35° (h). The trigonometric function that relates the opposite leg to an angle with the hypotenuse is sine:
sin 35° = (Opposite leg to 35°) / hypotenuse
sin 35° = h/(75 ft)
Solving for h:
(75 ft) sin 35°=h
h=75 sin 35° ft
h=75 (0.573576436) ft
h=43.01823270 ft
h=43 ft
Answer: T<span>he bottom of the balloon is 43 ft from the ground</span>
40.9 hg * 100g/1 hg = 4090 g
The correct answer to this question is the polynomial function would be distributed
Answer:
A. ![\frac{82}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B82%7D%7B3%7D)
Step-by-step explanation:
Step 1: We know .3333... is
, we rewrite the equation as ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
![27\frac{1}{3}\\ \frac{1+(27)(3)}{3}\\\frac{1+81}{3}\\\frac{82}{3}\\](https://tex.z-dn.net/?f=27%5Cfrac%7B1%7D%7B3%7D%5C%5C%20%5Cfrac%7B1%2B%2827%29%283%29%7D%7B3%7D%5C%5C%5Cfrac%7B1%2B81%7D%7B3%7D%5C%5C%5Cfrac%7B82%7D%7B3%7D%5C%5C)
Therefore the answer would be A. ![\frac{82}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B82%7D%7B3%7D)