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Studentka2010 [4]
3 years ago
9

Write an equation where 45 is the product.

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
3 0

Okay...

1 * 45

3 * 15

5 * 9

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

nydimaria [60]3 years ago
3 0
9 * 5 = 45
5 * 9 = 45
15 * 3 = 45
3 * 15 = 45
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10/7 or 1 3/7. I hope this helps,

Step-by-step explanation:

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Solve x + 3y = 9<br> 3x – 3y = -13 (1 point)
zavuch27 [327]

Answer:

(-1, 10/3)

x = -1

y = 10/3

Step-by-step explanation:

To solve a system, one of the methods you can use is <u>elimination</u>. To use elimination, you need <u>a variable to have the same coefficient in BOTH equations</u>. Since both equations have "3y", with the same coefficient (3), we can use this method.

We want to eliminate a variable by cancelling it out. Since positive 3y PLUS negative 3y is 0, the variable in eliminated. ADD each of the terms in the equations together.

.        x + 3y = 9

<u>+    3x – 3y = -13</u>

.     4x – 0y = -4           3y - 3y = 0        

.             4x = -4            Divide both sides by 4 to isolate 'x'

.               x = -1              Solved for the x-coordinate

Since we know one variable, 'x', we can easily find the other, 'y'. Substitute 'x' with -1 in any of the equations. Then, isolate 'x'.

x + 3y = 9

(-1) + 3y = 9

-1 + 1 + 3y = 9 + 1      Add 1 to both sides to cancel out left side.

3y = 9 + 1          Add on the right side (9 + 1 = 10)

3y = 10              Divide both sides by 3 to isolate 'y'

y = 10/3             Solved for the y-coordinate

Put the 'x' and 'y' coordinates together in an ordered pair, which you write as (x, y).

The solution to the system is (-1, 10/3).

5 0
3 years ago
Solve algebraically: <br> Y = x^2 + 5x - 17 <br> Y = x - 5
Ksenya-84 [330]

Answer:

2

Step-by-step explanation:

What you could do is fill in 2 for the equation and y would equal -3 so for the first one it's like

y= 2^2 + 5(2) -17

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In the second y it would be something like

y= 2 - 5 which would equal y= -3

so x=2

3 0
4 years ago
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