Change each mixed number into an equal improper fraction. a. 17⁄16 b. 115⁄9 c. 305⁄7 d. 1010⁄13 e. 243⁄5 f. 1291⁄2
2 answers:
A. 23⁄16<span> (16 × 1 + 7 = 23)</span>
<span>b. </span>104⁄9<span> (9 × 11 + 5 = 104)</span>
<span>c. </span>215⁄7<span> (7 × 30 + 5 = 215)</span>
<span>d. </span>140⁄13<span> (13 × 10 + 10 = 140)</span>
<span>e. </span>123⁄5<span> (5 × 24 + 3 = 123)</span>
<span>f. </span>259⁄2<span> (2 × 129 + 1 = 259)</span>
A.) 1 1/16
b.) 12 7/9
c.) 43 4/7
d.) 77 9/13
e.) 48 3/5
f.) 645 1/2
I hope this helps :)
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12 goes into 75 6 times with a remainder of 3. So the answer will be 6 remainder 3
Six hundred two thousand hundred seven.
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I think that the answer would be B beacuse both of them are negitive
Answer:
3, 5, 8, 13
Step-by-step explanation:
aₙ = aₙ₋₁ + aₙ₋₂
a₃ = a₂ + a₁ = 2 + 1 = 3
a₄ = a₃ + a₂ = 3 + 2 = 5
a₅ = a₄ + a₃ = 5 + 3 = 8
a₆ = a₅ + a₄ = 8 + 5 = 13
