Question

WEDNESDAY: Use the quadratic formula to solve the following: 3x^2 - 6x-12 = 0*

Answer 1

Answer:

a.) 3.236 or -1.236

Step-by-step explanation:

Used an online calculator for this answer...

Using the Quadratic Formula where

$x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }\\x = \frac{ -(-6) \pm \sqrt{(-6)^2 - 4(3)(-12)}}{ 2(3) }\\x = \frac{ 6 \pm \sqrt{36 - -144}}{ 6 }\\x = \frac{ 6 \pm \sqrt{180}}{ 6 }$

The discriminant b^2−4ac > 0

so, there are two real roots.

Simplify the radical...

$x = \frac{ 6 \pm 6\sqrt{5}\, }{ 6 }\\x = \frac{ 6 }{ 6 } \pm \frac{6\sqrt{5}\, }{ 6 }\\x = 1 \pm \sqrt{5}\,$

This simplifies to...

$x = 3.23607\\x = -1.23607$