× 10^-3 is 2,000 times greater than 1. 9 × 10-6. It is also times greater than 9. 5 × 10^-4

Mathematics

1 answer:

Gennadij [26K]2 years ago

8 0

Answer:

1.9 × 10^-6.

Step-by-step explanation:

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The bill is $62.78 the tax on the bill is 8% how much tax is owed

Ivahew [28]

Answer:

$5.0224

Step-by-step explanation:

8%=0.08

0.08*62.78=5.0224

3 0

2 years ago

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3 and 1/4 minus 5/8 please help!

Lesechka [4]

3 1/4 is equal to 13/4 or 26/8.

26/8 - 5/8 = 21/8

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2 years ago

A circle with a radius of 15 yards contains a sector with an area of 609 yde. Find the measure of

kondaur [170]

Answer: 310.3° or 5.41 radians.

Step-by-step explanation:

The area of a circle of radius R is calculated as:

A = pi*R^2

Now, if we have a sector of an angle θ degrees, the area of that sector is:

A = (θ/360°)*pi*R^2

In this case, we know that:

R = 15yd

And the area of the sector is 609 yd^2

Then we can replace these two values in the equation to get:

609yd^2 =(θ/360°)*3.14*(15yd)^2

(609yd^2)*360°/(3.14*(15yd)^2) = θ = 310.3°

And we want the angle also in radians.

We know that:

3.14 rad = 180°

(3.14 rad/180°) = 1

Then:

310.3° = 310.3°*(3.14 rad/180°) = (310.3°/180°)*3.14 rad = 5.41 radians.

4 0

2 years ago

Write the equation of the perpendicular bisector of . Point B is located at (–3, 1), and point C is located at (1, 5).

maxonik [38]

The equation of perpendicular bisector of BC is

$y=-x+2$

Further explanation:

A perpendicular bisector passes through the mid-point of a line so to get an ordered pair from which the perpendicular bisector will pass we need to find the mid-point of BC.

$Mid-point = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )\\Here\\(x_1,y_1) = (-3,1)\\(x_2,y_2) = (1,5)\\Putting\ values\ in\ formula\\M = (\frac{-3+1}{2} , \frac{1+5}{2} )\\= (\frac{-2}{2} ,\frac{6}{2})\\= (-1, 3)$