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bulgar [2K]
4 years ago
11

Which of the following is the endpoint of the altitude of a regular pyramid

Mathematics
1 answer:
larisa [96]4 years ago
4 0
It’s either vertex or base
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6⁄10 _______ 9⁄12 A. > B. ≤ C. = D.
Ivanshal [37]
6/10 is equal to 0.60
9/12 is equal to 0.75
your answer is not above for D but if D is < then that would be the correct answer :)
7 0
3 years ago
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4. The Emerson First National Bank is lending you money to buy a new car. The loan agreement will probably state
BlackZzzverrR [31]

Answer:

D. liability​

Step-by-step explanation:

The Emerson First National Bank is lending you money to buy a new car.

Before an agreement will be reached for any Organization to lend someone money there have to be something like a collateral.

The agreement will in it's document state that there must be a form of a reliability to hold on, such that if something's happen to the car, or you don't meet the paying up time, or something happens to you,they will see something to hold on.

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3 years ago
Which model best fits this set of data?
Jobisdone [24]

we are given points as

(-2,-4)

(0,2)

(1,5)

we can points

and then we can join them

After that we can get idea about it's shape

we can see that

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so, this is linear model

Hence, option-C................Answer

7 0
3 years ago
Which of the following can be used to prove that the triangle EFG is a right triangle.
Leviafan [203]
If you use a ruler and if it's more than 120° its not a right triangle it has to be 120°
8 0
3 years ago
I need help ASAP! It's urgent.. PLISSSSS​
natali 33 [55]

Answer:

a) 6 mins

b) 70km/h

c) t= 45

Step-by-step explanation:

a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km

Duration

= 16 -10

= 6 minutes

b) Average speed

= total distance ÷ total time

Total time

= 24min

= (24÷60) hr

= 0.4 h

Average speed

= 28 ÷0.4

= 70 km/h

c) Average speed= total distance/ total time

Average speed

= 80km/h

= (80÷60) km/min

= 1⅓ km/min

1⅓= 28 ÷(t -24)

<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>

\frac{4}{3}(t -24)= 28

\frac{4}{3}t - 32= 28

\frac{4}{3}t= 32 +28

\frac{4}{3}t= 60

t= 6 0\div  \frac{4}{3}

t= 45

*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.

Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)

5 0
4 years ago
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