the angles on the opposite sides of a quadrilateral touching the circumference adds up to 180 degrees
so,
(21x-2) + (38x +5) = 180
21x+38x −2+5=180
59x+3=180
59x=177
x=3
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The answer is C! Sorry if u get it wrong or I’m too late
Answer:
Step-by-step explanation:
Given the simultaneous equation
3x+4y=15. Equation 1
3x-y=30. Equation 2
Using elimination method
Sutract equation 2 from 1
Then, will have
3x-3x+4y--y=15-50. -×-=+
4y+y=-15
5y=-15
Divide Both sides by 5
y=-15/5
y=-3
From equation 2
3x-y=30
3x--3=30
3x+3=30
3x=30-3
3x=27
Divide both side by 3
x=27/3
x=9
Then, x=9 and y=-3
Answer:
x=82
Step-by-step explanation:
