Determine the time needed to deliver 72 papers at a rate of 9 papers in 18 minuets

1 answer:

monitta3 years ago

3 0

Hey there,

Question : Determine the time needed to deliver 72 papers at a rate of 9 papers in 18 minuets

Answer :
9 papers = 18 min
1 paper = 18 / 9
= 2 min
72 papers = 2 x 72
= 144 mins

Hope this helps :))

~Top♥

You might be interested in

Can someone help please what get doesn't show on these graphs

Julli [10]

Answer: The answer is no solution

Step-by-step explanation: if we try to get x to one side we subtract 2x from 2x on both sides and get 4 < 3 which is not true.

7 0

3 years ago

A candy factory made 54 boxes of chocolates. Each box weighs 2 pounds. They packed the boxes in 6 cases with the same number of

Lunna [17]

There was 18 pounds of chocolate in each case

3 0

3 years ago

Read 2 more answers

Helpppppo me with this pleaseeee

Troyanec [42]

Answer:

I think a but I am not 100 percent sure

Step-by-step explanation:

5 0

3 years ago

F(x) = e^-x . Find the equation of the tangent to f(x) at x=-1

natima [27]

Answer:

The equation of the tangent line is given by the following equation:

$\displaystyle y - \frac{1}{e} = \frac{-1}{e} \bigg( x - 1 \bigg)$

General Formulas and Concepts:

Algebra I

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate
y₁ - y coordinate
m - slope

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

*Note:

Recall that the definition of the derivative is the slope of the tangent line.

Step 1: Define

Identify given.

$\displaystylef(x) = e^{-x} \\x = -1$

Step 2: Differentiate

[Function] Apply Exponential Differentiation [Derivative Rule - Chain Rule]:
$\displaystyle f'(x) = e^{-x}(-x)'$
[Derivative] Rewrite [Derivative Rule - Multiplied Constant]:
$\displaystyle f'(x) = -e^{-x}(x)'$
[Derivative] Apply Derivative Rule [Derivative Rule - Basic Power Rule]:
$\displaystyle f'(x) = -e^{-x}$