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givi [52]
3 years ago
12

Determine the time needed to deliver 72 papers at a rate of 9 papers in 18 minuets

Mathematics
1 answer:
monitta3 years ago
3 0
Hey there,

Question : <span>Determine the time needed to deliver 72 papers at a rate of 9 papers in 18 minuets

Answer : 
9 papers = 18 min
1 paper = 18 / 9
             = 2 min
72 papers = 2 x 72
                 = 144 mins

Hope this helps :))

<em>~Top♥</em>
</span>
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It takes Jeremy 6 hours to paint a room. If it takes 4 hours for Jeremy and Marcus to paint the room together, how long does it
ASHA 777 [7]

Answer:

12 D. Is the answer

Step-by-step explanation:

The equation we will use is  

1

6

+  

1

x

=  

1

4

. Solve the equation by multiplying each term by the LCM of the denominator, 12x. The equation is now 2x + 12 = 3x. We solve and find x = 12. It will Marcus 12 hours to paint the room alone.

7 0
3 years ago
The point A,B,C and D represent the complex number Z1,Z2,Z3 and Z4 and O is the origin. If OABC is a parallelogram, and Z1=1+3i
aleksley [76]

Complex numbers are divided into two parts; real and imaginary parts. The value of Z3 is 5+ 8i

Given that:

Z_1 = 1 + 3i

Z_2 = 4 + 5i

Since O is the origin, then:

C = OA + OB

This means that:

Z_3 = Z_1 + Z_2

So, we have:

Z_3 = 1 + 3i + 4 + 5i

Collect like terms

Z_3 = 1 + 4+ 3i  + 5i

Z_3 = 5+ 8i

Hence, complex number Z3 is 5+ 8i

Read more about complex numbers at:

brainly.com/question/18509723

8 0
3 years ago
Someone do this real quick for me
SIZIF [17.4K]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
QUESTION IN THE ATTACHMENT
eimsori [14]

Answer:

A. The sum of the first 10th term is 100.

B. The sum of the nth term is n²

Step-by-step explanation:

Data obtained from the question include:

Sum of 20th term (S20) = 400

Sum of 40th term (S40) = 1600

Sum of 10th term (S10) =..?

Sum of nth term (Sn) =..?

Recall:

Sn = n/2[2a + (n – 1)d]

Sn is the sum of the nth term.

n is the number of term.

a is the first term.

d is the common difference

We'll begin by calculating the first term and the common difference. This is illustrated below:

Sn = n/2 [2a + (n – 1)d]

S20 = 20/2 [2a + (20 – 1)d]

S20= 10 [2a + 19d]

S20 = 20a + 190d

But:

S20 = 400

400 = 20a + 190d .......(1)

S40 = 40/2 [2a + (40 – 1)d]

S40 = 20 [2a + 39d]

S40 = 40a + 780d

But

S40 = 1600

1600 = 40a + 780d....... (2)

400 = 20a + 190d .......(1)

1600 = 40a + 780d....... (2)

Solve by elimination method

Multiply equation 1 by 40 and multiply equation 2 by 20 as shown below:

40 x equation 1:

40 x (400 = 20a + 190d)

16000 = 800a + 7600. ........ (3)

20 x equation 2:

20 x (1600 = 40a + 780d)

32000 = 800a + 15600d......... (4)

Subtract equation 3 from equation 4

Equation 4 – Equation 3

32000 = 800a + 15600d

– 16000 = 800a + 7600d

16000 = 8000d

Divide both side by 8000

d = 16000/8000

d = 2

Substituting the value of d into equation 1

400 = 20a + 190d

d = 2

400 = 20a + (190 x 2)

400 = 20a + 380

Collect like terms

400 – 380 = 20a

20 = 20a

Divide both side by 20

a = 20/20

a = 1

Therefore,

First term (a) = 1.

Common difference (d) = 2.

A. Determination of the sum of the 10th term.

First term (a) = 1.

Common difference (d) = 2

Number of term (n) = 10

Sum of 10th term (S10) =..?

Sn = n/2 [2a + (n – 1)d]

S10 = 10/2 [2x1 + (10 – 1)2]

S10 = 5 [2 + 9x2]

S10 = 5 [2 + 18]

S10 = 5 x 20

S10 = 100

Therefore, the sum of the first 10th term is 100.

B. Determination of the sum of the nth term.

First term (a) = 1.

Common difference (d) = 2

Sum of nth term (Sn) =..?

Sn = n/2 [2a + (n – 1)d]

Sn = n/2 [2x1 + (n – 1)2]

Sn = n/2 [2 + 2n – 2]

Sn = n/2 [2 – 2 + 2n ]

Sn = n/2 [ 2n ]

Sn = n²

Therefore, the sum of the nth term is n²

6 0
3 years ago
A luxury resort is offering an incentive discount. If you book your room six months in advance, you will save 15% off the price
Anna [14]

Answer:the total discounted cost for your stay is $1948.2

Step-by-step explanation:

If you book your room six months in advance, you will save 15% off the price of the room. You decide to take advantage of the offer and book a room for 6 nights. If the original price per night for the room is $382, this means that the value of the discount would be

15/100 × 382 = 0.15 × 382 = $57.3

The cost of the room for a night would be

382 - 57.3 = $324.7

Since you are staying for six nights,

the total discounted cost for your stay would be

324.7 × 6 = $1948.2

8 0
3 years ago
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