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Firdavs [7]
3 years ago
6

d^2y/dx^2=sqrt(1+(dy/dx)^2 state the order of the given ordinary differential equation. Determine whether the equation is linear

or nonlinear.
Mathematics
1 answer:
Georgia [21]3 years ago
5 0
This is a second-order ODE since the highest order derivative is 2 (from \dfrac{\mathrm d^2y}{\mathrm dx^2}).

It's not linear because it doesn't take the form

F\left(\dfrac{\mathrm d^2y}{\mathrm dx^2},\dfrac{\mathrm dy}{\mathrm dx},y,x\right)=0\iff f_2(x)\dfrac{\mathrm d^2y}{\mathrm dx^2}+f_1(x)\dfrac{\mathrm dy}{\mathrm dx}+f_0(x)y+g(x)=0

and it's not possible to rewrite it as such.
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tony had 1 1/2 gallons of orange juice. He drank 2/7 of the orange juice he had. How mucj orange juice did Tony drink?
Sever21 [200]
There are several information's of immense importance already given in the question.
Amount of juice that Tony actually had = 11/2 gallons
Amount of juice that Tony drank = (11/2) * (2/7) gallons
                                                    = 11/7 gallons
From the above deduction, we can easily conclude that the amount of juice that Tony drank was 11/7 gallons.
6 0
3 years ago
Solve x² + 11x +18=0 by factoring.
kirill [66]
-(11+sqrt(121-4*18))/2 = -(11 +sqrt(49))/2 = -9

Or

-(11-sqrt(121-4*18))/2 = -(11-sqrt(49))/2 = -2

D is the answer
5 0
2 years ago
Activity 1<br>Calculate the following:<br>1. 68% of 418,​
il63 [147K]

Answer:

284.24

Step-by-step explanation:

by multiplying 0.68 to 418 we get 68% of 418

7 0
3 years ago
Read 2 more answers
Given that (-4,-4) is on the graph of f(x), find the corresponding point for the function 1/2 f(x)
marusya05 [52]

Answer:

(-4, -2)

Step-by-step explanation:

The x-coordinate would stay the same, but the y-coordinate would be halved.  Thus, the corresponding point would be (-4, -2).

3 0
3 years ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
3 years ago
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