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Firdavs [7]
3 years ago
6

d^2y/dx^2=sqrt(1+(dy/dx)^2 state the order of the given ordinary differential equation. Determine whether the equation is linear

or nonlinear.
Mathematics
1 answer:
Georgia [21]3 years ago
5 0
This is a second-order ODE since the highest order derivative is 2 (from \dfrac{\mathrm d^2y}{\mathrm dx^2}).

It's not linear because it doesn't take the form

F\left(\dfrac{\mathrm d^2y}{\mathrm dx^2},\dfrac{\mathrm dy}{\mathrm dx},y,x\right)=0\iff f_2(x)\dfrac{\mathrm d^2y}{\mathrm dx^2}+f_1(x)\dfrac{\mathrm dy}{\mathrm dx}+f_0(x)y+g(x)=0

and it's not possible to rewrite it as such.
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un carro que se mueve con velocidad constante recorre 120 km en 75 minutos,¿en que tiempo recorrera el carro una distancia de 20
Ivan

Answer:

320 minutos

Step-by-step explanation:

4 0
3 years ago
A miniature quadcopter is located at xi = −1.75 m and yi = −5.70 m at t = 0 and moves with an average velocity having components
Black_prince [1.1K]

The quadcopter's average velocity is given in terms of change in position by

\vec v_{\rm av}=\dfrac{\Delta x}{\Delta t}\,\vec\imath+\dfrac{\Delta y}{\Delta t}\,\vec\jmath

where \Delta x=x_f-x_i, the difference in the quadcopter's final and initial positions and \Delta t=(1.60-0)\,\mathrm s=1.60\,\mathrm s.

The x-component of the average velocity is 2.70 m/s, so

2.70\dfrac{\rm m}{\rm s}=\dfrac{x_f-(-1.75\,\mathrm m)}{1.60\,\rm s}\implies \boxed{x_f=2.57\,\mathrm m}

and the y-component is -2.50 m/s, so

-2.50\dfrac{\rm m}{\rm s}=\dfrac{y_f-(-5.70\,\mathrm m)}{1.60\,\rm s}\implies\boxed{y_f=-9.70\,\mathrm m}

4 0
3 years ago
What is the sum of 2 1/3, 3 5/6 and 6 2/3
Andreas93 [3]
2 1/3+ 3 5/6+ 6 2/3
= 7/3+ 23/6+ 20/3
= 14/6+ 23/6+ 40/6
= 77/6
= 12 5/6

The final answer is 12 5/6~
5 0
3 years ago
Round 66.42 to the nearest hundredth
Musya8 [376]

Answer:

66.42

Step-by-step explanation:

66.42 is already rounded to the nearest hundredth.

3 0
3 years ago
A pole that is 3.4 m tall casts a shadow that is 1.54 m long. At the same time, a nearby building casts a shadow that is 35.75 m
inna [77]

Answer:

The building would be 78.92 meters tall.

Step-by-step explanation:

If the shodow of a 3.4m tall pole is 1.54m tall, and you have the shadow's height, then you make a cross, multiply-divide ratio table.

5 0
3 years ago
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