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Firdavs [7]
3 years ago
6

d^2y/dx^2=sqrt(1+(dy/dx)^2 state the order of the given ordinary differential equation. Determine whether the equation is linear

or nonlinear.
Mathematics
1 answer:
Georgia [21]3 years ago
5 0
This is a second-order ODE since the highest order derivative is 2 (from \dfrac{\mathrm d^2y}{\mathrm dx^2}).

It's not linear because it doesn't take the form

F\left(\dfrac{\mathrm d^2y}{\mathrm dx^2},\dfrac{\mathrm dy}{\mathrm dx},y,x\right)=0\iff f_2(x)\dfrac{\mathrm d^2y}{\mathrm dx^2}+f_1(x)\dfrac{\mathrm dy}{\mathrm dx}+f_0(x)y+g(x)=0

and it's not possible to rewrite it as such.
You might be interested in
A company developed the following linear model to help budget annual expenses over time. In this model, x represents the number
ollegr [7]
The only reasonable answer I could think for this is "A.<span>The company's expense budget for 2009 was $189,785."
I believe this because since x is the years after 2009 then you wouldn't times that by the expense budget for that year or any year eliminating B and C. When finding the total expense budget for this you would have to take in account the budget from 2009 so that would lead it to add 189,758. Since we are talking about after 2009 then D would be eliminated since 2008 is before 2009. 
I hope this helps! Good luck!</span><span>
</span>
6 0
2 years ago
Mha fans be like..........
artcher [175]

Answer:

ewwwwwwwwwwwwwwwwwwwwwwwwwww

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
27.38 + 384 -<br> I don’t know the answer can I please have some help
Katen [24]

Answer:

411.38

Step-by-step explanation:

When you add 27.38 and 384 together, you get 411.38.

3 0
2 years ago
The formula for the surface area of a cylinder with radius r and height h is at times twice the product of the
MrMuchimi

Answer:

<em>2\pi \: rh + 2\pi {r}^{2}  = 2(t \times  {r}^{2} )</em>

Step-by-step explanation:

The TSA of the cylinder

2\pi \: rh + 2\pi {r}^{2}

In Mathematics, 'is' is =

Twice means 2( )

Product means ×

So we have

2\pi \: rh + 2\pi {r}^{2}  = 2(t \times  {r}^{2} )

as the answer.

6 0
2 years ago
Ignoring leap days, the days of the year can be numbered 1 to 365. Assume that birthdays are equally likely to fall on any day o
faust18 [17]

Answer:

Follows are the solution to the given question:

Step-by-step explanation:

They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.

S=365^n

This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.

P(x)=\frac{1}{365^{n}}

if x is between 1 and 365 as well as the occurrence is just all similarly possible

In point i:

That somebody mentions their birthday throughout the party

Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.

In point ii:

Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.

In point iii:

Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.

6 0
2 years ago
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