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Aloiza [94]
3 years ago
14

Enrique was asked to solve the equation His steps are shown.

Mathematics
2 answers:
mr_godi [17]3 years ago
7 0

Answer:

be more proscie

Step-by-step explanation:

valkas [14]3 years ago
6 0

there is nothing Shown on the steps

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Find the number of steel ball bearings, each of diameter 0.7 cm, that can be made from 1kg of steel, given that 1cm cubed of ste
dimulka [17.4K]

Answer:

Ball Bearing Volume = (4 / 3) * PI * radius ^3

Volume = (4 / 3) * 3.14159265 * (.35)^3

Volume = (4 / 3) * 3.14159265 * 0.042875

Volume = 0.17959438 cc

1 cc of steel = 7.8 g

Volume of 1 kg of steel = 1,000 cc / 7.8 g per cc

1 kg = 128.205 cc

Number of ball bearings we can make = 128.205 / 0.17959438

Equals 713.86

Step-by-step explanation:

7 0
3 years ago
Calculate the mean and standard deviation for the average yards rushed by
Amiraneli [1.4K]

Question:

A sample of cans of peaches was taken from a warehouse, and the content of each can mearsed for weight. the sample means was 486g with stand deviation 6g. state the weight percentage of cans with weight:

Draw normal curve to help - split into 8 section ( i can't draw it here)

a) 34.13% of cans will be between 480g and 486g.

b) 13.59 + 2.15 + 0.13= 15.87% of cans greater than 492g.

Look at the Stand Dev Graph where the give you the number

Step-by-step explanation:

Let me give you a different question and i will answer it, which you help you answer your question.

8 0
1 year ago
Ms. Rhodes gave 9 of the 36 students that are in her class a passing grade. Which
tatuchka [14]
It would be B. 9*4=36. 25% is 1/4
8 0
3 years ago
A relative maximum of the function y = ln(x)/x is:
dezoksy [38]
Take the deritivive
remember
the deritivive of f(x)/g(x)=(f'(x)g(x)-g'(x)f(x))/(g(x)^2)
so
deritiveive is ln(x)/x is
remember that derivitive of lnx is 1/x
so

(1/x*x-1lnx)/(x^2)=(1-ln(x))/(x^2)
the max occurs where the value is 0
(1-ln(x))/(x^2)=0
times x^2 both sides
1-lnx=0
add lnx both sides
1=lnx
e^1=x
e=x
see if dats a max or min
at e/2, the slope is positive
at 3e/2, the slope is negative
changes from positive to negative at x=e

that means it's a max

max at x=e
I realize I didn't find the max point, so

sub back
ln(x)/x
ln(e)/e
1/e
the value of the max would be 1/e occuring where x=e

4th option is answer (1/e) because that is the value of the maximum (which happens at x=e)
4 0
3 years ago
Read 2 more answers
How to solve this part
san4es73 [151]

Try this solution (the way shown is not the shortest one):

The task on the left part:

1. note, the point P and R have coordinates (-4;-4) and (-3;-2).

2. using the coordinates of points P and R it is possible to make up the equation of the required line:

\frac{x-x_P}{x_R-x_P} =\frac{y-y_P}{y_R-y_P}; \ => \ \frac{x+4}{-3+4}=\frac{y+4}{-2+4}; \ => \ \frac{x+4}{1}=\frac{y+4}{2}  \ or \ y=2x+4

The task of the right part:

1. note, the common view of the equation of the line is y=kx+b, where b - an intersection point of the Y-axis and the given line; k=QR/PQ.

2. according the picture b= -5, k=4/1=5, so <u>y= -4x-5</u>

4 0
3 years ago
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