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1 year ago

Calculate the mean and standard deviation for the average yards rushed by

Mathematics

1 answer:

Amiraneli [1.4K]1 year ago

8 0

Question:

A sample of cans of peaches was taken from a warehouse, and the content of each can mearsed for weight. the sample means was 486g with stand deviation 6g. state the weight percentage of cans with weight:

Draw normal curve to help - split into 8 section ( i can't draw it here)

a) 34.13% of cans will be between 480g and 486g.

b) 13.59 + 2.15 + 0.13= 15.87% of cans greater than 492g.

Look at the Stand Dev Graph where the give you the number

Step-by-step explanation:

Let me give you a different question and i will answer it, which you help you answer your question.

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2 years ago

Find the general solution of the differential equation. (use c for the constant of integration.) dr dt = 8et 1 − e2t

natulia [17]

Try this solution:
if given dr/dt=8e^t -e^(2t), then
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2 years ago

In a purely monopolistic market with a demand curve P = -Q / 10 + 2000, to maximize profit the firm provides the application at

Rudiy27

Answer: hello your question lacks some data hence I will be making an assumption to help resolve the problem within the scope of the question

answer:

≈ 95 units ( output level )

Step-by-step explanation:

Given data :

P = 2000 - Q/10

TC = 2Q^2 + 10Q + 200 ( assumed value )

The output level where a purely monopolistic market will maximize profit

at MR = MC

P = 2000 - Q/10 ------ ( 1 )

PQ = 2000Q - Q^2 / 10 ( aka TR )

MR = d (TR ) / dQ = 2000 - 2Q/10 = 2000 - Q/5

TC = 2Q^2 + 10Q + 200 ---- ( 2 )

MC = d (TC) / dQ = 4Q + 10

equating MR = MC

2000 - Q/5 = 4Q + 10

2000 - 10 = 4Q + Q/5

1990 = 20Q + Q

∴ Q = 1990 / 21 = 94.76 ≈ 95 units ( output level )

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Answer:

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