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klio [65]
3 years ago
12

How to solve this part

Mathematics
1 answer:
san4es73 [151]3 years ago
4 0

Try this solution (the way shown is not the shortest one):

The task on the left part:

1. note, the point P and R have coordinates (-4;-4) and (-3;-2).

2. using the coordinates of points P and R it is possible to make up the equation of the required line:

\frac{x-x_P}{x_R-x_P} =\frac{y-y_P}{y_R-y_P}; \ => \ \frac{x+4}{-3+4}=\frac{y+4}{-2+4}; \ => \ \frac{x+4}{1}=\frac{y+4}{2}  \ or \ y=2x+4

The task of the right part:

1. note, the common view of the equation of the line is y=kx+b, where b - an intersection point of the Y-axis and the given line; k=QR/PQ.

2. according the picture b= -5, k=4/1=5, so <u>y= -4x-5</u>

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Follow the math steps provided in picture! 10 points and a 5 star rating to answer something (Ofc it has to make sense.)
Aneli [31]

Solving the algebraic equations given, the missing numbers in the boxes can be known as shown in the steps below.

Given the equation, ⅔(x - 1) = ⅕(2x - 3) + 1

First, apply the distribution property to open the bracket.

Thus:

⅔x - ⅔ = ⅖x - ⅗ + 1

⅔x - ⅔ = ⅖x + ⅖

  • Subtract ⅖x from both sides

⅔x - ⅖x - ⅔ = ⅖

4/15x - ⅔ = ⅖

  • Add ⅔ to both sides

4/15x = ⅖ + ⅔

4/15x = 16/15

  • Multiply both sides by 15/4

x = 16/15 × 15/4

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Given the equation, 3c - 3 + 2(3c + 1) = - (3c + 1)

  • Open the bracket using distributive property

3c - 3 + 6c + 2 = -3c - 1

  • Add like terms

9c - 1 = -3c - 1

  • Add 3c to both sides

9c + 3c - 1 = -1

12c - 1 = -1

  • Add 1 to both sides

12c = -1 + 1

12c = 0

  • Divide both sides by 12

c = 0

Learn more about algebraic equations on:

brainly.com/question/7784687

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2 years ago
Plz help I really need this to be correct.
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I’m with the guy above me
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Danny's jump rope is 6 meters long.how many decimeters is his jump rope?
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6m = 60 decimeters
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