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3 years ago

Kerri said that the product of 3.93 and 0.07 would be about 4 and would have two decimal places. Is she correct?

Mathematics

2 answers:

oee [108]3 years ago

8 0

Answer:

No.

Step-by-step explanation:

This type of problem is actually a trick problem. The question indicates that the PRODUCT of 3.93 and 0.07 would be about 4. The question is referring to the answer of the two values Multiplied to each other.

To visualize the question, we have:

3.93 x 0.07

This would give us:

0.2751

Kerri would be correct if she was looking for the SUM of the two values.

This would be:

3.93 + 0.07

This would give us:

Therefore in trick problems like this ones, it is better to look at what exactly is being asked.

JulijaS [17]3 years ago

7 0

Answer:

No, Kerri is not correct because to visualize this question we have 3.93 times 0.07 and this would give us 0.2751. Kerri would be correct if she was looking for the sum of the two numbers.

This was similar to the other person who answered the question but I tried to make it more into a whole paragraph. Hope this helps :)

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Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M’N’O’P’Q’.

N76 [4]

Answer:
slope of M'N' = 1

Explanation:
First, we will need to get the coordinates of points M' and N':
We are given that the dilation factor (k) is 0.8
Therefore:
For point M':
x coordinate of M' = k * x coordinate of M
x coordinate of M' = 0.8 * 2 = 1.6
y coordinate of M' = k * y coordinate of M
y coordinate of M' = 0.8 * 4 = 3.2
Therefore, coordinates of M' are (1.6 , 3.2)

For point N':
x coordinate of N' = k * x coordinate of N
x coordinate of N' = 0.8 * 3 = 2.4
y coordinate of N' = k * y coordinate of N
y coordinate of N' = 0.8 * 5 = 4
Therefore, coordinates of M' are (2.4 , 4)

Then, we can get the slope of M'N':
slope = (y2-y1) / (x2-x1)
For M'N':
slope = (3.2-4) / (1.6-2.4)
slope = 1

Hope this helps :)

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3 years ago

laura has a mass of 60kg and is sitiing 265cm from the fulcrum of a seesaw. bill has a mass of 50kg. how far from the fulcrum mu

pickupchik [31]

Answer:

318 cm.

Step-by-step explanation:

Let x represent the distance between Bill and fulcrum.

We have been given that Laura has a mass of 60 kg and is sitting 265 cm from the fulcrum of a seesaw. Bill has a mass of 50 kg.

To balance the seesaw, the product of Laura's weight and her distance from fulcrum of seesaw should be equal to the product of Bill's weight and his distance from fulcrum of seesaw as:

$50\text{ kg}\cdot x=60\text{ kg}\cdot 265\text{ cm}$

$\frac{50\text{ kg}\cdot x}{50\text{ kg}}=\frac{60\text{ kg}\cdot 265\text{ cm}}{50\text{ kg}}$

$x=\frac{6\cdot 265\text{ cm}}{5}$

$x=\frac{6\cdot 53\text{ cm}}{1}$

$x=318\text{ cm}$

Therefore, Billy should be 318 cm far from the fulcrum to balance the seesaw.

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