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arlik [135]
4 years ago
7

Kerri said that the product of 3.93 and 0.07 would be about 4 and would have two decimal places. Is she correct?

Mathematics
2 answers:
oee [108]4 years ago
8 0

Answer:

No.

Step-by-step explanation:

This type of problem is actually a trick problem. The question indicates that the PRODUCT of 3.93 and 0.07 would be about 4. The question is referring to the answer of the two values Multiplied to each other.

To visualize the question, we have:

3.93 x 0.07

This would give us:

0.2751

Kerri would be correct if she was looking for the SUM of the two values.

This would be:

3.93 + 0.07

This would give us:

4

Therefore in trick problems like this ones, it is better to look at what exactly is being asked.

JulijaS [17]4 years ago
7 0

Answer:

No, Kerri is not correct because to visualize this question we have 3.93 times 0.07 and this would give us 0.2751.  Kerri would be correct if she was looking for the sum of the two numbers.

This was similar to the other person who answered the question but I tried to make it more into a whole paragraph. Hope this helps :)

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F(x)=23x−1 and g(x)=−4x+6.
USPshnik [31]

The transformation occurs from function g is a vertical translation 6 units down.

<h3>What is Transformation?</h3>

A function f, usually with some geometrical underpinning, that maps a set X to itself, i.e. f : X → X.

Given:

g(x) = 4x + 6

g(x) = 0

4x + 6=0

x= -6/4

Now,

f(-6/4) = 2 - 1

=-1

By seeing g(x), we can say that  function g is a vertical translation 6 units down.

Learn more about transformation here:

https://brainly.in/question/29403318

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3 0
2 years ago
The length of a rectangle is 12 in and the perimeter is 56 what us the width of the rectangle
Aleks [24]
Hi there!

We can find the perimeter of a rectangle by using the following formula:

perimeter = 2 × width + 2 × length

In the question, we are given the following data: the length of the rectangle is 12 in and the perimeter is 56. Let's substitute this into our formula!

56 = 2 × width + 2 × 12
Multiply first.

56 = 2 × width + 24
Now subtract 24 from both sides.

32 = 2 × width
And finally, to find the width of the rectangle, divide both sides of the equation by 2.

16 = width
(we can eventually switch sides in the equation).

width = 16
~ Hope this helps you!
3 0
3 years ago
Why are asymptotes important in rational function graphs
leonid [27]

Answer:

when sketching the curves of functions.

Step-by-step explanation:

There is a wide range of graph that contain asymptotes and that includes rational functions, hyperbolic functions, tangent curves, and more. Asymptotes are important guides when sketching the curves of functions. This is why it’s important that we know the properties, general forms, and graphs of each of these asymptotes.

6 0
2 years ago
Given points A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1), which of the following proves that
damaskus [11]

Similar triangles may or may not have equal side lengths

Triangles ABC and DEF are similar by SSS theorem

<h3>How to determine the similarity statement</h3>

The coordinates of the two triangles are:

A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1)

Calculate the lengths of both triangles using the following distance formula

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

For triangle ABC, we have:

AB = \sqrt{(0 -4)^2 + (0 -0)^2} = 4

BC = \sqrt{(4 -0)^2 + (0 -2)^2} = 2\sqrt 5

CA = \sqrt{(0 -0)^2 + (0 -2)^2} = 2

For triangle DEF, we have:

DE = \sqrt{(0 -2)^2 + (0 -0)^2} = 2

EF = \sqrt{(2 -0)^2 + (0 -1)^2} = \sqrt 5

FD = \sqrt{(0 -0)^2 + (1 -0)^2} = 1

Divide corresponding sides of the triangles to calculate the scale factor k

k = \frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD}

This gives

k = \frac{4}{2} = \frac{2\sqrt 5}{\sqrt 5} = \frac{2}{1}

Evaluate the quotients

k = 2 = 2 = 2

Since the quotients are equal, then the triangles are similar

Hence, triangles ABC and DEF are similar by SSS theorem

Read more about similar triangles at:

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3 0
2 years ago
Find the average value of the function over the given interval and all values of x in the interval for which the function equals
MrRissso [65]

The average value of f(x)=4x^3-3x^2 over [-1, 3] is

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8 0
3 years ago
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