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vlabodo [156]
4 years ago
8

assume that when adults with smartphones are randomly selected, 44% use them in meetings or classes. If 10 adult smartphones use

rs are randomly selected find the probability that fewer than 3 of them
Mathematics
1 answer:
tensa zangetsu [6.8K]4 years ago
7 0

Solution: The given random experiment follows Binomial distribution with n=10,p=0.44

Let X be the number of adults who use their smartphones in meetings or classes.

Therefore, we have to find:

P(X

We know the binomial model is:

P(X=x)=\binom{n}{x} p^{x} (1-p)^{n-x}

\therefore P(X

                       =\binom{10}{0}0.44^{0}(1-0.44)^{12-0}+\binom{10}{1}0.44^{1}(1-0.44)^{10-1}+\binom{10}{2}0.44^{2}(1-0.44)^{10-2}

                       =1 \times 1 \times 0.0030 + 10 \times 0.44 \times 0.0054 + 45 \times 0.1936 \times 0.009672

                       =0.0030+0.0238+0.0843

                       =0.1111

Therefore, the probability that fewer than 3 of them is 0.1111

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