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ipn [44]
3 years ago
13

If you have a balance of $270 in your bank account each month you deposit $45 let January=1 February=2 and so on. Write any equa

tion for the situation using equation to find the balance in June
Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0

Answer:

$540

Step-by-step explanation:

We are given that the initial balance in the bank account is $270.

We are then told that every month $45 is added to the account.

To find the equation that tells us the balance at any point in time assuming no interest is added or money is taken out, we can first understand the constant, y=270.

This gives us the initial value of the balance and any changes to the balance will start from this point.

Let x be the time in months.

if we let y=270 + 45x, we find the value of the function accounting for the addition of money every month.

Assuming money is put in during January; substituting the number of months as x=6 (since it is June), we can find the balance in June.

y=270 +45(6)=540

Hence, the balance in June is $540

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A code consists of two digit numbers chosen from 00-99 (i.E 00, 01, 02…..99) followed by two different letters of the alphabet.
Ede4ka [16]

Answer: 1/67600

Step-by-step explanation:

probability that the code is 43MZ:

Probability = (Total Required outcome / total possible outcomes)

Possible outcomes (digit) = (00,.............. ..., 99)

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4 0
3 years ago
9. Calcule el valor de la fuerza que experimenta un ascensor cuando levanta 150 kg en los siguientes casos: a) Cuando asciende c
GenaCL600 [577]

Answer:

a) La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) Por la fuerza de tensión sobre el cable del ascensor.

Step-by-step explanation:

a) La fuerza neta experimentada por el ascensor (F), en newtons, es:

F = m\cdot a (1)

Donde:

m - Masa, en kilogramos.

a - Aceleración, en metros por segundo cuadrado.

Si sabemos que m = 150\,kg y a = 4\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = 600\,N

La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) Si sabemos que m = 150\,kg y a = -6\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = -900\,N

La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) De manera simplificada, el ascensor experimenta dos fuerzas que definen la fuerza y aceleración netas: (i) La fuerza de tensión sobre el cable que traslada el ascensor y el peso total del ascensor, opuesta a la anterior y en función de la aceleración gravitacional. Puesto que la masa no varía en ningún caso, se concluye que el peso es constante, entonces la diferencia de valores se debe a la fuerza por tensión del cable. En el descenso, es fuerza es menor que en el ascenso.

8 0
3 years ago
10 POINTS! HELP ITS DUE SOON!!
Naddika [18.5K]

Answer:

10

Σ [n^2]

i=1

Step-by-step explanation:

Hope I helped? I inserted it into a calc and I also got 385 for something if its useful))

8 0
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