Answer:
Step-by-step explanation:
Integrating each term with respect to x, we get:
x^3 x^2
f(x) = 9--------- + 4------- - 4x + C
3 2
We are told that if x = 0, f(x) = -7, and so C must equal - 7.
The solution is
x^3 x^2
f(x) = 9--------- + 4------- - 4x - 7, or f(x) = 3x^3 + 2x^2 - 4x - 7
3 2
This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
14 cups. 2.33 (2 1/3 in decimal form) multiplied by 6 (the number of children) equals 13.98 (round to 14)
Answer:
(2P + G) feet/min
Step-by-step explanation:
Speed of the panda = P
Speed of the giraffe = P + G
Thus,
Speed of Panda + Speed of Giraffe = approaching time
= P + P + G
= <u>2P + G</u>
Thus, The panda and the giraffe are approaching each other at a rate
of <u>(2P + G) ft/min</u>
<u></u>
<em>Hope it helps :)</em>
The last one would be incorrect. We are looking for PART of whatever N is. Multiply by the whole number 25 is definitely not what we want to do.
Hope I helped!
