Question

The growth rate of the sunflower from day 14 to day

Answer 1

Option B) h = 4.5t – 27 is the equation of the straight line that best models the height h, in centimeters, of the sunflower t days after it begins to grow.

                     

From the above graph we can see that from day 14 to day 35 , it is a straight line.

And equation of a straight line is   y = mx + c  or   y – y1 = m(x – x1)

                               Where, m =slope of the line

                                             c = intercept

the equation can be rewritten as  h – h1  = m(t – t1)                    (1)

So, to find the equation of line , first we will calculate the slope of the line.

To find the slope : m = (h2 – h1 ) / (t2 – t1)                     (2)

From the graph and the table given, the coordinates (t1 , h1 ) and ( t2 , h2 ) are (14 , 36.6) and (35, 131) respectively.

Putting these values in equation (2), we get

                 m = (131 – 36.6)/(35 – 14)

                 m =  94.4/21

                 m  = 4.5

now to find the equation of line we put the values in equation (1), we get

h – 36.6 = 4.5(t – 14)

h – 36.6 = 4.5t – 63

h = 4.5t -63 + 36.6

h = 4.5t -27

Hence the equation of the line is ,   option B) h = 4.5t -27

Learn more about the straight line here : brainly.com/question/6977417

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