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kherson [118]
3 years ago
6

The y-value for the midline is equal to?

Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0

Answer:

(max y + min y)/2

the next answer is k=4

Step-by-step explanation:

exis [7]3 years ago
6 0

Answer:

answer is b (max y + min y)/2

Step-by-step explanation:

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Y-9=26<br> Can anyone help me with this question
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Step-by-step explanation:

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When a pair of six sided dice is rolled , each with faces numbered 1 to 6,is rolled once,what is the probability that the result
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In probability, there are hint clues that you must be vigilant of. When it tells you to find the probability of event 1 'or' event 2, you must ADD their individual probabilities. When it tells you to find the probability of event 1 'and' event 2, you must MULTIPLY their individual probabilities. 

Now, you have two dices. You are asked to find the probability of getting a face of 3, 4 or 5. The probability of each face of a dice is 1/6, because there are a total of 6 faces. When you use two dices, it becomes 2/12 or still 1/6. So, the total probability of getting either 3, 4 or 5 is: 1/6 + 1/6 + 1/6 = 1/2. However, you still have to multiply this with the total probability of getting a prime numbers which are 1, 2, 3 and 5. Thus, 1/6 + 1/6 + 1/6 + 1/6 = 2/3

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5 0
2 years ago
How do you do this? conculsion statements.
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The conclusion should be letter B, if Karl runs 1mi, then he runs 5280 ft. In fact, that option is the only one in which you combine the information you have to get a conclusion.
5 0
3 years ago
Read 2 more answers
A clerk at Agency Y has determined that at speeds of 25 pages per minute it is typical for 3 out of every 100 pages she photocop
nalin [4]

Answer:

180 pages

Step-by-step explanation:

Since her photocopy session is 25 pages per minute, the total number of pages photocopied in 4 hour session can be calculated as;

number of pages = time × speed

                                 = (4 × 60) × 25

                                 = 240 ×25

                                 = 6000 pages

Thus, number of pages photocopied in 4 hours is 6000.

For every 100 pages, 3 would contain some type of printing error. The number of pages she expect with printing error during 4 hour session can be determined as;

           = \frac{6000}{100} × 3

           = 60 × 3

           = 180 pages

The expected number of pages with printing error during 4 hour photocopying session is 180 pages.

3 0
3 years ago
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