10x10x10x10x10x10=1000000

means 10x10x10x10x10x10
as it's basically saying 10 is multiplied by itself 6 times which gives you 1000000
Answer:

Step-by-step explanation:
Since two sides of the triangle are equal in length, we can conclude that
is an isosceles triangle. With this information, we can draw an isosceles triangle to find
. Since the base angles of an isosceles triangle are equal, we can solve for
:
(Angle sum of triangle is
)
(Base angles of isosceles triangles are equal, there is an image attached to show that
is one of the base angles)


Hope this helps :)
Answer:
Step-by-step explanation:
It's given in this question,
m∠2 = 41°, m∠5 = 94° and m∠10 = 109°
Since, ∠2 ≅ ∠9 [Alternate interior angles]
m∠2 = m∠9 = 41°
m∠8 + m∠9 + m∠10 = 180° [Sum of angles at a point of a line]
m∠8 + 41 + 109 = 180
m∠8 = 180 - 150
m∠8 = 30°
Since, m∠2 + m∠7 + m∠8 = 180° [Sum of interior angles of a triangle]
41 + m∠7 + 30 = 180
m∠7 = 180 - 71
m∠7 = 109°
m∠6 + m∠7 = 180° [linear pair of angles]
m∠6 + 109 = 180
m∠6 = 180 - 109
= 71°
Since m∠5 + m∠4 = 180° [linear pair of angles]
m∠4 + 94 = 180
m∠4 = 180 - 94
m∠4 = 86°
Since, m∠4 + m∠3 + m∠9 = 180° [Sum of interior angles of a triangle]
86 + m∠3 + 41 = 180
m∠3 = 180 - 127
m∠3 = 53°
m∠1 + m∠2 + m∠3 = 180° [Angles on a point of a line]
m∠1 + 41 + 53 = 180
m∠1 = 180 - 94
m∠1 = 86°
Step-by-step explanation:
the first one is 2 that appears most while the second is 20 and 3
I think it's this answer <span>C.A high voltage current can be transformed into a low voltage current.</span>